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3 years ago

Which of the following is an example of an unbalanced force?

Physics

2 answers:

r-ruslan [8.4K]3 years ago

6 0

Answer:

Explanation:

because the motion is changing as it slows down mark brainliest to help me out :)

TEA [102]3 years ago

3 0

D because the person pushing the stroller is putting more force than the stroller

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Which explains why more energy is released in nuclear reactions then in chemical reactions

beks73 [17]

Nuclear reaction you are literally splitting an atom and in a chemical reaction you are not

7 0

3 years ago

An oil film with refractive index 1.48 and thickness 290 nm is floating on water and illuminated with white light at normal inci

VikaD [51]

Answer:

572.3 nm

Explanation:

$n_{oil}$ = refractive index of the oil film = 1.48

$t_{oil}$ = thickness of the oil film = 290 nm

$\lambda$ = wavelength of the dominant color

m = order

Using the equation

$2 n_{oil} t_{oil} = (m + 0.5) \lambda$

For m = 0

$2 (1.48) (290) = (0 + 0.5) \lambda$

$\lambda$ = 1716.8 nm

For m = 1

$2 (1.48) (290) = (1 + 0.5) \lambda$

$\lambda$ = 572.3 nm

For m = 2

$2 (1.48) (290) = (2 + 0.5) \lambda$

$\lambda$ = 343.4 nm

Hence the dominant color wavelength is 572.3 nm

8 0

3 years ago

While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the

nirvana33 [79]

Haven't taken physics but I would assume if her friend is standing in front of her that you would add up the speeds and get 30 km/hr.

7 0

3 years ago

Read 2 more answers

Use the Bohr model to address this question. When a hydrogen atom makes a transition from the 5 th energy level to the 2nd, coun

iris [78.8K]

Answer:

A. 2.82 eV

B. 439nm

C. 59.5 angstroms

Explanation:

A. To calculate the energy of the photon emitted you use the following formula:

$E_{n1,n2}=-13.4(\frac{1}{n_2^2}-\frac{1}{n_1^2})$ (1)

n1: final state = 5

n2: initial state = 2

Where the energy is electron volts. You replace the values of n1 and n2 in the equation (1):

$E_{5,2}=-13.6(\frac{1}{5^2}-\frac{1}{2^2})=2.82eV$

B. The energy of the emitted photon is given by the following formula:

$E=h\frac{c}{\lambda}$ (2)

h: Planck's constant = 6.62*10^{-34} kgm^2/s

c: speed of light = 3*10^8 m/s

λ: wavelength of the photon

You first convert the energy from eV to J:

$2.82eV*\frac{1J}{6.242*10^{18}eV}=4.517*10^{-19}J$

Next, you use the equation (2) and solve for λ:

$\lambda=\frac{hc}{E}=\frac{(6.62*10^{-34} kg m^2/s)(3*10^8m/s)}{4.517*10^{-19}J}=4.39*10^{-7}m=439*10^{-9}m=439nm$

C. The radius of the orbit is given by:

$r_n=n^2a_o$ (3)

where ao is the Bohr's radius = 2.380 Angstroms

You use the equation (3) with n=5:

$r_5=5^2(2.380)=59.5$

hence, the radius of the atom in its 5-th state is 59.5 anstrongs

8 0

3 years ago

A 42 Watt light bulb is connected to a 12 volt source of potential

abruzzese [7]

Answer:

The natural medium emanating from the Sun and other very hot sources (now recognised as electromagnetic radiation with a wavelength of 400-750 nm), within which vision is possible.

Explanation:

just the way it is

8 0

3 years ago