An atom that has 7 protons 7 electrons and 6 neutrons

compare the different ways a musician changes the pitch while playing a stringed instrument or playing a wind instrument

alexdok [17]

(This is from experience so sorry if it's wrong but) When wind instruments are played, sometimes the notes go flat or sharp depending on the speed the player blows air into the instrument as well as the warmth of the air. When playing a string instrument, the pitch can be changed in many ways. For example, when the player places their fingers on the string depending on which part of the tip of the finger you use, the tone of the sound and sometimes the pitch, changes. Looking at the question in a different way, you can change the pitch and the range of notes you can reach on the instrument (both wind and string) by changing the note you tune your instrument to. Hope this helps!!

3 0

4 years ago

A student put her ear on one end of a long piece of lead. She asked her friend to

Ludmilka [50]

1) The length of the lead is 1700 m

2) The frequency of the wave is 400 Hz

Explanation:

1)

The wave in this problem is a sound wave, which is produced by the vibrations of the particles of air. It is a type of longitudinal wave (which means that the vibrations occur back-and-forth along the direction of propagation of the wave).

The speed of a sound wave in air is approximately

v = 340 m/s

In this problem, the sound wave is heard after a time of

t = 5 s

after the shot. Therefore, the distance travelled by the wave in this time (and therefore, the length of the lead) is

$d=vt=(340)(5)=1700 m$

2)

The frequency of a wave is the number of complete cycles made by the wave in one second.

For the wave in this problem, we are told that the wave has 2000 whole wavelengths in 5 seconds: this means that the wave completes 2000 cycles in 5 seconds. Therefore, we can find the frequency by setting up the following proportion:

$\frac{2000}{5}=\frac{x}{1}$

where x is the number of cycles made in 1 second. Solving for x,

$x=\frac{2000\cdot 1}{5}=400 s^{-1}$

Therefore, the frequency of the wave is

$f=400 Hz$

Learn more about waves and frequency:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

7 0

4 years ago

Please help!! :)

Andrews [41]

Answer:

Option D. 9.47 V

Explanation:

We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:

Resistor 1 (R₁) = 20 Ω

Resistor 2 (R₂) = 30 Ω

Resistor 3 (R₃) = 45 Ω

Equivalent Resistance (R) =?

R = R₁ + R₂ + R₃ (series connections)

R = 20 + 30 + 45

R = 95 Ω

Next, we shall determine the current in the circuit. This can be obtained as follow:

Voltage (V) = 45 V

Equivalent Resistance (R) = 95 Ω

Current (I) =?

V = IR

45 = I × 95

Divide both side by 95

I = 45 / 95

I = 0.4737 A

Finally, we shall determine, the voltage across R₁. This can be obtained as follow:

NOTE: Since the resistors are in series connection, the same current will pass through them.

Current (I) = 0.4737 A

Resistor 1 (R₁) = 20 Ω

Voltage 1 (V₁) =?

V₁ = IR₁

V₁ = 0.4737 × 20

V₁ = 9.47 V

Therefore, the voltage across R₁ is 9.47 V.

8 0

3 years ago

I will give more points <br>for this thank you I u helped<br>me

scZoUnD [109]

Answer:

weight = mass×gravity

15×9.8
147N

<h2>stay safe healthy and happy.</h2>

6 0

3 years ago

how much time would it take for the sound of a thunder to travel 1,500 meters if sound travelers at a speed of 330 m/sec?

inysia [295]

(1,500 meters) x (1 sec/330 meters) =

(1,500 / 330) (meters-sec/meters) =

4.55 seconds

8 0

3 years ago