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quester [9]
3 years ago
13

A 15-foot ladder is leaning against a house with the base of the ladder 4 feet from the house. How high up the house does the la

dder reach? Round to the nearest tenth of a foot.
Physics
1 answer:
eimsori [14]3 years ago
5 0

Answer:

height of house to ladder reach is 14 ft

Explanation:

Given data

ladder = 15 ft

base  = 4 ft

to find out

height of house

solution

we know this is triangle shape so we apply here

so we consider here x is ladder and y is base and z is height

so

by pythagoras theorem

z² + y² = x²

so here

z² = x² -y²

put value

z² = 15² - 4²

z² = 209

z = 14.45 = 14

so height of house to ladder reach is 14 ft

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a = 5.83 \times 10^{-4} m/s^2

Explanation:

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so here we can say that net force on the system is zero here

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so here we know that

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acceleration of boy = 1.50 m/s^2

now we know that

F = ma

F = 70(1.50) = 105 N

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3 years ago
A 2. 0 μf and a 4. 0 μf capacitor are connected in series across an 8. 0-v dc source. what is the charge on the 2. 0 μf capacito
Nezavi [6.7K]

voltage across 2.0μf capacitor is 5.32v

Given:

C1=2.0μf

C2=4.0μf

since two capacitors are in series there equivalent capacitance will be

[tex] \frac{1}{c} = \frac{1}{c1} + \frac{1}{c2} [/tex]

c =  \frac{c1 \times c2}{c1 + c2}

=  \frac{2 \times 4}{2 + 4}

=1.33μf

As the capacitance of a capacitor is equal to the ratio of the stored charge to the potential difference across its plates, giving: C = Q/V, thus V = Q/C as Q is constant across all series connected capacitors, therefore the individual voltage drops across each capacitor is determined by its its capacitance value.

Q=CV

given,V=8v

= 1.33 \times 10 {}^{ - 6}  \times 8

= 10.64 \times 10 {}^{ - 6}

charge on 2.0μf capacitor is

\frac{Qeq}{2 \times 10 {}^{ - 6} }

=  \frac{10.64 \times 10 {}^{ - 6} }{2 \times 10 {}^{ - 6} }

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learn more about series capacitance from here: brainly.com/question/28166078

#SPJ4

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1 year ago
Write fulk form of FPS?<br>​
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2 years ago
A 4.00 kg block is suspended from a spring with k 500 N/m. A 50.0 g bullet is fired into the block from directly below with a sp
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Answer:

a. A = 0.1656 m

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Explanation:

Given

mB = 4.0 kg , mb = 50.0 g = 0.05 kg , u₁ = 150  m/s , k = 500 N / m

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To find the amplitude of the resulting SHM using conserver energy

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A = 0.1656 m

b.

The percentage of kinetic energy

%E = Es / Ek

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Ek = ¹/₂ * mb * v² = 0.05 kg * 150² m/s = 1125 N

% E = 13.72 / 1125 = 0.01219 *100

% E = 1.219

6 0
3 years ago
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