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Sedbober [7]
3 years ago
5

Select the correct answer from each drop-down menu.

Chemistry
1 answer:
stealth61 [152]3 years ago
5 0

Answer:

Light energy; chemical

Explanation:

The light energy of the Sun is converted into chemical energy by the plants.

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How many Al atoms are there in 40.5 g of Al foil? Al:27
andrew-mc [135]

Answer:

c) 9.03 x 10^23

Explanation:

find the molar mass of Al

Al is 27.0 grams

Then use that, to find the number of moles in Aluminum.

Then use Avogadro's number which is 6.02 * 10^23

After that, write all of that down with dimensional analysis.

40.5 g * 1 mol/ 27.0 g of Al  * 6.02 x 10^23 / 1mol

As your final answer, you will get 9.03 * 10^23 atoms with sig figs.

Hope it helped!

4 0
3 years ago
What is the iupac name of ch3ch2ch2ch2ch2ch3
Alborosie

Answer:

hexane

Explanation:

3 0
3 years ago
Help me fast! Please!
tatyana61 [14]

The letter D because the more the N on the left have more on the right.

6 0
3 years ago
What are the correct coefficients when this equation is balanced?
larisa86 [58]

4, 3, 1

Explanation:

Sb has four on the right, so it needs four on the left. It's all alone, so <u>4</u>.

O2 comes in pairs, so you only need <u>3</u> of those to get six oxygens.

And 1 is the place holder for the right side since we got the left to match perfectly.

6 0
3 years ago
For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
Diano4ka-milaya [45]
The balanced chemical reaction is given as follows:

<span>2 KClO3(s) → 2 KCl(s) + 3 O2(g)

The starting amount of the reactant are given above. These values would be used for the calculations. We do as follows:

</span>2.72 g KClO3 (1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 1.06 g O2
<span>
0.361 g KClO3 </span>(1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 0.14 g O2
<span>
83.6 kg KClO3 (1000g / 1kg) </span>(1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 3275.76 g O2
<span>
22.5 mg KClO3</span> (1 g / 1000 mg) (1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 0.009 g O2
4 0
3 years ago
Read 2 more answers
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