Answer:
Molarity = 1.93 mol.L⁻¹
Explanation:
Molarity is the unit of concentration used to specify the amount of solute in given amount of solution. It is expressed as,
Molarity = Moles / Volume of Solution ----- (1)
Data Given;
Mass = 11.3 g
Volume = 100 mL = 0.10 L
First calculate Moles for given mass as,
Moles = Mass / M.mass
Moles = 11.3 g / 58.44 g.mol⁻¹
Moles = 0.1933 mol
Now, putting value of Moles and Volume in eq. 1,
Molarity = 0.1933 mol ÷ 0.10 L
Molarity = 1.93 mol.L⁻¹
All of these elements have an electron configuration<span> that ends with </span><span>s1</span><span>. Francium's properties have not been determined experimentally, because so far there has not been enough of it to experiment with </span>Sodium is group 1/IA, the alkali metals, on the periodic table. Therefore, the other elements in this group will have similar properties as sodium. These would include, lithium<span>, potassium, </span>rubidium<span>, and </span>cesium<span>.
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Answer:
When a magnesium atom reacts with an oxygen atom, magnesium gives up its two valence electrons and becomes a positively charged ion, i.e. a cation, Mg2+ … The cation and the anion will then be attracted to each other by way of the electrostatic force of attraction → an ionic bond is formed.
Explanation:
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