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weqwewe [10]
3 years ago
10

When forming a chemical bond only the ________ electrons participate in the bonding process.

Chemistry
2 answers:
matrenka [14]3 years ago
8 0
The outer shell electrons are only involved in the bonding process since they are the only 'incomplete' shell and it needs to be fulfilled by another element. 
hichkok12 [17]3 years ago
6 0

<u>Answer:</u> When forming a chemical bond, outer shell electrons participate in the bonding process.

<u>Explanation:</u>

A chemical bond is defined as the bond which is formed by the combination of atoms or ions.

There are two types of chemical bonds:

  • <u>Ionic bonds:</u> They are defined as the bonds which are formed by the complete transfer of valence (outer shell) electrons from cation (positively charged ions) to anion (negatively charged ions). <u>For Example:</u> NaCl, BaSO_4 etc...
  • <u>Covalent bonds:</u> They are defined as the bonds which are formed by the sharing of valence electrons between the atoms. <u>For Example:</u> HCl, CH_4 etc..

Inner shell electrons are the electrons which are tightly held by the electrons. They are called as core electrons.

Outer shell electrons are the electrons which are not tightly held by the electrons. They are called as valence electrons.

Hence, when forming a chemical bond, outer shell electrons participate in the bonding process.

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cubic measurements

Explanation:

i.e. cubic meter or cubic centimeter

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What mass of lead (II) chloride is produced when 200.0 mL of a 0.250 M solution of sodium chloride is mixed with 200.0 mL of a 0
kow [346]

Answer:

Option d. 6.95 g

Explanation:

First of all, we state the reaction:

2NaCl + Pb(NO₃)₂ → PbCl₂ +  2NaNO₃

We determine the moles of each reactant, to state the limiting

Firstly we convert volume frm mL to L

0.200 L . 0.250M = 0.05 moles of NaCl

0.200L . 0.250M = 0.05 moles of Pb(NO₃)₂

Acording to stoichiometry we know that relation is 1:2, so the limiting reagent is the NaCl.

For 1 mol of Pb(NO₃)₂ I need 2 moles of NaCl

For 0.05 moles of Pb(NO₃)₂ I would need, the double → 0.1 moles

(We only have, 0.05 moles of NaCl)

Stoichiometry to the formed product is 2:1

From 2 moles of NaCl I produce 1 mol of PbCl₂

From 0.05 moles I would produce, the half → 0.025 moles

Let's convert the moles to mass → 0.025 mol . 278.1 g / 1mol = 6.95 g

8 0
3 years ago
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Andru [333]
•••••••••••••••••••••••••••••
6 0
2 years ago
What would the pOH of a solution be if the pH is 9.4
Alika [10]
<h2>Answer:</h2>

pOH = 4.6

<h2>Explanations:</h2>

The sum of pH and pOH of a solution is 14as shown:

pH+pOH=14

Given the following parameter

pH = 9.4

Substitute the given parameters into the formula to have:

\begin{gathered} 9.4+pOH=14 \\ pOH=14-9.4 \\ pOH=4.6 \end{gathered}

Hence the pOH of the solution of pH of 9.4 is 4.6

4 0
1 year ago
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