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3 years ago

When forming a chemical bond only the ________ electrons participate in the bonding process.

2 answers:

8 0

The outer shell electrons are only involved in the bonding process since they are the only 'incomplete' shell and it needs to be fulfilled by another element.

hichkok12 [17]3 years ago

6 0

Answer: When forming a chemical bond, outer shell electrons participate in the bonding process.

Explanation:

A chemical bond is defined as the bond which is formed by the combination of atoms or ions.

There are two types of chemical bonds:

Ionic bonds: They are defined as the bonds which are formed by the complete transfer of valence (outer shell) electrons from cation (positively charged ions) to anion (negatively charged ions). For Example: NaCl, $BaSO_4$ etc...
Covalent bonds: They are defined as the bonds which are formed by the sharing of valence electrons between the atoms. For Example: HCl, $CH_4$ etc..

Inner shell electrons are the electrons which are tightly held by the electrons. They are called as core electrons.

Outer shell electrons are the electrons which are not tightly held by the electrons. They are called as valence electrons.

Hence, when forming a chemical bond, outer shell electrons participate in the bonding process.

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Thousand of molecules are called

kozerog [31]

Answer:

monomers

Explanation:

Thousands of molecules are called monomers

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3 years ago

What is the minimum amount of heat required to completely melt 40.0 grams of ice at its melting point?

elena55 [62]

If 20.0 grams of ice takes about 6680j...then 40.0 grams of ice would take ___ .

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3 years ago

why is uranium 235 the most commonly used isotope for nuclear fission in current uses in nuclear power generation?

Pachacha [2.7K]

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3 years ago

A particular reaction, A- products, has a rate that slows down as the reaction proceeds. The half-life of the reaction is found

Thepotemich [5.8K]

Explanation:

Half life of zero order and second order depends on the initial concentration. But as the given reaction slows down as the reaction proceeds, therefore, it must be second order reaction. This is because rate of reaction does not depend upon the initial concentration of the reactant.

a. As it is a second order reaction, therefore, doubling reactant concentration, will increase the rate of reaction 4 times. Therefore, the statement a is wrong.

b. Expression for second order reaction is as follows:

$\frac{1}{[A]} =\frac{1}{[A]_0} +kt$

the above equation can be written in the form of Y = mx + C

so, the plot between 1/[A] and t is linear. So the statement b is true.

Expression for half life is as follows:

$t_{1/2}=\frac{1}{k[A]_0}$

As half-life is inversely proportional to initial concentration, therefore, increase in concentration will decrease the half life. Therefore statement c is wrong.

Plot between A and t is exponential, therefore there is no constant slope. Therefore, the statement d is wrong

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3 years ago

A valid lewis structure of __________ cannot be drawn without violating the octet rule. a valid lewis structure of __________ ca

Oxana [17]

A valid Lewis structure of IF3 cannot be drawn without violating the octet rule.

Answer: IF3 (Iodine Trifluoride)

This is because, I (Iodine) and F (Fluorine) both have odd number of valence electrons (7) which also means that there are too many valence electrons in the valence shell.

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3 years ago