Answer:
0.6
Step-by-step explanation:
Given that the spinner has 5 equal sections numbered 1 to 5.
- Total Sample Space, n(S)=5
Multiples of 2 in 1 to 5 are: {2,4}
Number less than than 3 are:{1,2}
Since we are required to find the probability of the spinner stopping on a number that is a multiple of 2 or is less than 3, we take the union of both sets.
{2,4} 
{1,2} ={1,2,4}
Number of Outcomes=3
Therefore,
Probability of the spinner stopping on a number that is a multiple of 2 or is less than 3 
The answer to number 5 is 128
Answer:
Step-by-step explanation:
Pattern 1 consists of
small squares (here n = 1 and 
).
Pattern 2 consists of
small squares (here n = 2 and 
).
Pattern 3 consists of
small squares (here n = 3 and 
).
Thus, pattern n consists of
small squares.
We presume your cost function is
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral
This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000
