Answer:
C.) ![K_a = \frac{[H^+][H_2PO_4^-]}{[H_3PO_4]}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cfrac%7B%5BH%5E%2B%5D%5BH_2PO_4%5E-%5D%7D%7B%5BH_3PO_4%5D%7D)
Explanation:
The general structure for a Ka expression is:
![K_a = \frac{[H^+][A^-]}{[HA]}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
In this expression,
-----> Ka = equilibrium constant
-----> [A⁻] = base
-----> [HA] = acid
The products are in the numerator and the reactants are in the denominator. In this case, H₃PO₄ serves as an acid and H₂PO₄⁻ serves as a base.
As such, the equilibrium expression is:
A catalyst is a compound that accelerates a chemical reaction without getting used up in the process.
Un catalizador es un compuesto que acelera una reacción química sin ser agotado en el proceso.
Answer:
Molarity = 54.50 M
Explanation:
Molarity is defined as the number of moles of a solute in 1 liter of solution. It has mol/l unit.
Molar mass of glucose, C6H12O6 = (6*12) + (1*12) + (16*6)
= 72 + 12 + 96 = 180g/mol
Density of glucose solution = 1.03g/ml
Density in g/l = 1.03g/ml * 1ml/10^-3l
= 1030g/l
10.5% mass of glucose = 10.5/100 * 180
= 18.9g/mol
Molarity = density (g/l)/molar mass (g/mol)
= 1030/18.9
= 54.50 M
Answer:
25.155 gram
Explanation:
HCl(aq.) + NaOH(aq.) ⇒ NaCl + H2O
According the above equation equal number of moles of reactant are producing same number of moles of products.
Now, no. mole of HCl = 15.7/(1+35.5) = 0.43 moles
no. of moles of NaOH = 27/(23+16+1) = 0.675 moles
Since the amount of sodium hydroxide exceeds the amount of hydrochloric acid, the maximum amount of each substance participating in the reaction is HClν ν 0.43 moles .Therefore, the maximum amount of NaCl that can be produced is as follow
= (23+35.5)×0.43 = 25.155 gram
Answer : fluorine
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