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podryga [215]
3 years ago
5

Question 4 of 10

Physics
1 answer:
kiruha [24]3 years ago
5 0
B hey what do u know i took that test to
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What are the relationships between position, velocity, and acceleration as it relates to time?
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Velocity = distance /time
acceleration = velocity / time
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Cool air tends to...
IceJOKER [234]

Answer: C. Be more dense and flow under warm air.

Explanation:

think of a supermarket selling dairy products and when you open the fridge to get the milk, outside the supermarket is hot and inside the fridge is cold ice.

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2 years ago
A horizontal force of 50 N is applied to the object.
USPshnik [31]

Answer:

Mass of object (m) = 5.102 kg

Explanation:

Given:

Horizontal Force (F) = 50 N

Find:

Mass of object (m) = ?

Computation:

We know that, acceleration due to gravity (g) = 9.8 m/s²

⇒ Horizontal Force (F) = mg

⇒ 50 N = m (9.8 m/s²)

⇒ Mass of object (m) =  50 / 9.8

⇒ Mass of object (m) = 5.102 kg

Mass of object (m) is 5.1 kg (Approx)

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4 years ago
Set the initial bead height to 3.00 m. Click Play. Notice that the ball makes an entire loop. What is the minimum height require
strojnjashka [21]

Answer:

h> 2R

Explanation:

For this exercise let's use the conservation of energy relations

starting point. Before releasing the ball

       Em₀ = U = m g h

Final point. In the highest part of the loop

       Em_f = K + U = ½ m v² + ½ I w² + m g (2R)

where R is the radius of the curl, we are considering the ball as a point body.

      I = m R²

      v = w R

we substitute

       Em_f = ½ m v² + ½ m R² (v/R) ² + 2 m g R

       em_f = m v² + 2 m g R

Energy is conserved

       Emo = Em_f

       mgh = m v² + 2m g R

       h = v² / g + 2R

 

The lowest velocity that the ball can have at the top of the loop is v> 0

      h> 2R

3 0
3 years ago
Two children are pulling and pushing a 30.0 kg sled. The child pulling the sled is exerting a force of 12.0 N at a 45o angle. Th
irinina [24]
I'm not quite sure what happens to Fay so I didn't finish but hope it helps

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3 years ago
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