3 years ago

Are Styrofoam and wood the same temperature, if they are not what are each others temperature

Physics

1 answer:

Olenka [21]3 years ago

3 0

They are almost the same temperature!!

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The water in the plumbing in a house is at a gauge pressure of 350,000 pa. what force does this cause on the top of the tank ins

adelina 88 [10]

Use P=F/a
whereas P= 350000 and a=.9m2
substitute into the formula we get
350000=f/.9m2 multiply .9 on both sides as LHS=RHS WE get 315000 Newtons as the answer

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3 years ago

A car travels 200km in the first 2.5 hours of a trip. it stops half am hour and then travels final 200km in 2 hours. find the av

aksik [14]

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time 4.5

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7 0

3 years ago

A 250-lb block is subjected to a horizontal force P. The coefficient of friction between the block and surface is µs = 0.2. Dete

aev [14]

Answer:

force required to push the block = 219.714 lb

Explanation:

GIVEN DATA:

weight W of block = 250 lb

coefficient of friction = 0.2

consider equilibrium condition in x direction

$P*cos(30)-W*sin(30)-\mu _{s}N = 0$

$P*0.866-0.2N = 125$ .........................(1)

consider equilibrium condition in Y direction

$N-Wcos(30)-Psin(30)= 0$

$N-0.5P=216.503$ .....................(2)

SOLVING 1 and 2 equation we get N value

N = 326.36 lb

putting N value in either equation we get force required to push the block = 219.714 lb

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3 years ago

Design, analyze, and simulate a DC power supply to provide a nominal DC voltage of 2.4V and be able to supply a load current as

ella [17]

Answer:

Attached

Explanation:

4 0

3 years ago

A conveyor belt is used to send burgers through a grill- ing machine. If the grilling machine is 1.2m long and the burgers requi

puteri [66]

Answer:

$Rate = 1.71 burger/min$

Explanation:

Length of the conveyor belt is given as

$L = 1.2 m$

time taken to cook one burger is given as

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now we can find the speed of the belt as

$v = \frac{distance}{speed}$

$v = \frac{1.2}{168}$

$v = 7.14 \times 10^{-3} m/s$

Now we know that the distance between two burgers is given as 25 cm

$d = 0.25 m/burger$

now the production rate of burgers is given as

$Rate = \frac{v}{d}$

$Rate = \frac{7.14 \times 10^{-3} m/s}{0.25 m/burger}$

$Rate = 0.0286\frac{burger}{sec}$

$Rate = 0.0286\times 60\frac{burger}{min}$

$Rate = 1.71 burger/min$

8 0

3 years ago