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expeople1 [14]
3 years ago
7

What are the first five elementsof the periodic table?

Chemistry
1 answer:
Kamila [148]3 years ago
3 0
Hydrogen
Helium
Lithium
Beryllium
Boron
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Hi May I know how to balance this
almond37 [142]

Answer:

  2Ba₃(PO₄)₂ +6SiO₂ ⇒ P₄O₁₀ +6BaSiO₃

Explanation:

Equating coefficients, you get ...

  aBa₃(PO₄)₂ +bSiO₂ ⇒ cP₄O₁₀ +dBaSiO₃

For Ba: 3a = d

For P: 2a = 4c

For O: 8a +2b = 10c +3d

For Si: b = d

__

Expressing everything in terms of b and c, we get ...

  d = b

  a = b/3 = 2c

From the second, b = 6c, so we have ...

  a = 2c

  b = 6c

  c = c

  d = 6c

And we can write the equation with c=1 as ...

  2Ba₃(PO₄)₂ +6SiO₂ ⇒ P₄O₁₀ +6BaSiO₃

4 0
3 years ago
Please help <br><br> 10 POINTS!!!
salantis [7]
The answer would be C as in cat and D as in dog your welcome i hope this help
5 0
2 years ago
A metal used in hot water systems​
Basile [38]

Answer:

I think this would be iron

Explanation:

5 0
2 years ago
Calculate to three significant digits the density of chlorine pentafluoride gas at exactly and exactly . You can assume chlorine
slega [8]

Answer:

Density is 6.16g/L

Explanation:

<em>... at exactly -15°C and exactly 1atm...</em>

<em />

Using general gas law:

PV = nRT

We can find density (Ratio of mass and volume) in an ideal gas as follows:

P/RT = n/V

<em>To convert moles to grams we need to multiply the moles with Molar Weight, MW:</em>

n*MW = m

n = m/MW

P/RT = m/V*MW

P*MW/RT = m/V

<em>Where P is pressure: 1atm;</em>

<em>MW of chlorine pentafluoride: 130.445g/mol</em>

<em>R is gas constant: 0.082atmL/molK</em>

<em>And T is absolute temperature: -15°C+273.15 = 258.15K</em>

<em />

Replacing:

P*MW/RT = m/V

1atm*130.445g/mol / 0.082atmL/molK*258.15K = m/V

6.16g/L = m/V

<h3>Density of the gas is 6.16g/L</h3>

<em> </em>

7 0
2 years ago
If the pressure on a gas at -73°C is doubled but its volume is held constant, what will its final temperature be in degrees Cels
Gre4nikov [31]

Answer:

127°C

Explanation:

This excersise can be solved, with the Charles Gay Lussac law, where the pressure of the gas is modified according to absolute T°.

We convert our value to K → -73°C + 273 = 200 K

The moles are the same, and the volume is also the same:

P₁ / T₁ = P₂ / T₂

But the pressure is doubled so: P₁ / T₁ = 2P₁ / T₂

P₁ / 200K = 2P₁ / T₂

1 /2OOK = (2P₁ / T₂) / P₁

See how's P₁ term is cancelled.

200K⁻¹ = 2/ T₂

T₂ = 2 / 200K⁻¹  → 400K

We convert the T° to C → 400 K - 273 = 127°C

4 0
3 years ago
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