For Part A.
The absolute value of vector A is
<span>|A | = 6
This is simply the square root of the sum of the squares of the coordinates.
For Part B
Do the same thing as in Part A
| B | = </span>√14
<span>
Part C
Simply subtract the corresponding elements resulting in
(-3, 2, 7)
Part D
</span>√62
<span>
Part E
Yes</span>
Answer:
- Increase the concentration of the reactants
-increase the temperature
- introduce a catalyst
Answer:
Explanation:
Given that, .
Pressure around scuba is
P = 10^5 Pa
1 Pa = 1 N/m²
Then
P = 10^5 N/m²
Descending height
h = 10m
Change in force per unit square centimetre
We know that,
Pressure = Force / Area
Then,
Force / Area is the required question we are finding
Then,
Force / Area = 10^5 N / m²
So, let convert the m² to cm²
100cm = 1m
(100cm)² = (1m)²
10⁴cm² = 1m²
Then,
Force / Area = 10^5 N/m² × 1m² / 10⁴cm²
Force / Area = 10 N/cm²
So, the force per unit square centimeters is 10.
The strength of the thrust is 122 newtons.
The motion of the rocket is described by the second Newton's law, whose model is shown below:
(1)
Where:
- Thrust, in newtons
- Drag, in newtons
- Mass of the rocket, in kilograms
- Net acceleration of the rocket, in meters per square second
If we know that 
, 
and 
, then the strength of the thrust is:
The strength of the thrust is 122 newtons.
To learn more on Newton's laws, we kindly invite to check this verified question: brainly.com/question/13678295
