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lana [24]
3 years ago
13

A wind-tunnel experimentis performed on a 1/25scale model of a supersonic aircraft. The prototype aircraft flies at 450 m/s in c

onditions where the speed of sound is 250 m/s and the air density is 0.89kg/m3. The model aircraft is tested in a wind tunnel in which the speed of sound is 280m/s and the air density is 0.56kg/m3. The drag force on the model is 100N. What speed must the flow in the wind tunnel be for dynamic similitude, and what is the drag force on the prototype?

Physics
1 answer:
KengaRu [80]3 years ago
4 0

Answer: V = 504m/a

F = 4N

Explanation: please find the attached file for the solution

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A steel aircraft carrier is 370 m long when moving through the icy North Atlantic at a temperature of 2.0 °C. By how much does t
34kurt

Answer:

The carrier lengthen is 0.08436 m.

Explanation:

Given that,

Length = 370 m

Initial temperature = 2.0°C

Final temperature = 21°C

We need to calculate the change temperature

Using formula of change of temperature

\Delta T=T_{f}-T_{i}

\Delta T=21-2.0

\Delta T=19^{\circ}C

We need to calculate the carrier lengthen

Using formula of length

\Delta L=\alpha_{steel}\times L_{0}\times\Delta T

Put the value into the formula

\Delta L=1.2\times10^{-5}\times370\times19

\Delta L=0.08436\ m

Hence, The carrier lengthen is 0.08436 m.

8 0
3 years ago
To calculate the ideal mechanical advantage of a lever divide the input arm by the
Ivanshal [37]
To calculate the ideal mechanical advantage of a lever divide the input arm by the output arm. 
Mechanical advantage is the amount by which a machine can multiply an input force, calculated by dividing output Force in newtons by input force in newtons, while the ideal mechanical advantage is the mechanical advantage of a machine that has no friction, calculated by dividing the input distance by the output distance. 
6 0
3 years ago
Problem 9: Suppose you wanted to charge an initially uncharged 85 pF capacitor through a 75 MΩ resistor to 90.0% of its final vo
Bingel [31]

Answer:

t=14.678\times 10^{-3}s

Explanation:

Given:

Capacitance, C = 85 pF = 85 × 10⁻¹² F

Resistance, R = 75 MΩ = 75×10⁶Ω

Charge in capacitor at any time 't' is given as:

Q=Q_o(1-e^{-\frac{t}{RC}})

where,

Q₀ = Maximum charge = CE

E = Initial voltage

t = time

also, Q = CV

V= Final voltage = 90% of E = 0.9E

thus, we have

C\times 0.9E=CE(1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})

or

0.9=1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}

or

e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}=1-0.9=0.1

taking log both sides, we get

ln(e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})=ln(0.1)=ln(\frac{1}{10})

or

-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}=-ln(10)

or

t=75\times 10^6\ \times\ 85\times 10^{-12}\times ln{10}

or

t=14.678\times 10^{-3}s

3 0
3 years ago
A 1400 kg car is moving at 33.8 m/s when a force is applied the opposite direction of the car's motion. The car slows down to 21
zubka84 [21]

Solve for acceleration:

<em>a</em> = (21.4 m/s - 33.8 m/s) / (4.7 s)

<em>a</em> ≈ -2.6 m/s²

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The minus sign tells you the force points in the opposite direction of the car's motion. Its magnitude is always positive, so <em>F</em> = 3700 N.

3 0
3 years ago
Why is the same side of the Moon always visible from Earth?
son4ous [18]

Answer:

Explanation:

Answer

The true fact is that C is what happens in outer space.  Both rotations take 27.3 days.  

A: The exact opposite is true. It does rotate about it's axis.

B: Again this is just plain false. Given the way we observe it, the moon must be rotating around the earth.

D. they don't. 27.3 hours and 24 hours are not the same.

8 0
2 years ago
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