Question

Three objects are positioned along the x axis as follows: 4.4 kg at x = + 1.1 m, 3.7 kg at x = +0.80 m, and 2.9 kg at x = +1.6 m. The acceleration due to gravity is the same everywhere. What is the location of the center of gravity for this system? Group of answer choices

Answer 1

Answer:

the distance from the location of the center of gravity to the location of the center o mass for this system is 1.13m

Explanation:

Given that

m₁=4.4kg

x₁=+1.1m

m₂=3.7kg

x₂=+0.80m

m₃=2.9kg

x₃=+1.6m

The position of the center of mass is

         Xcm = [m₁x₁ +m₂x₂ +m₃x₃]/(m₁+m₂+m₃)

                = [(4.40kg)(1.1 m)+(3.70 kg)(0.80 m)+(2.90 kg)(1.60 m)]/(4.4 kg + 3.70 kg+2.90 kg)

              = 1.13 m

The position of the center of gravity is 1.13m

Therefore, the distance from the location of the center of gravity to the location of the center o mass for this system is 1.13m