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Artemon [7]
3 years ago
7

10. Given the relative abundance of the following naturally occurring isotope of silver, calculate the average atomic mass of si

lver. Show your work.
silver-107: 52.00% 106.905 amu
silver-109: 48.00% 108.905 amu
Chemistry
1 answer:
Kamila [148]3 years ago
8 0
106.905/52.00 equals 205.58
108.905/48.00 equals 226.88
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Explanation:

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As it is given that mass is 9.109 \times 10^{-31} kg. So, putting the given values into the above formula as follows.

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