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3 years ago

How may acres of land are estimated to be lost each day to development?

Engineering

1 answer:

Law Incorporation [45]3 years ago

3 0

175 acres per hour of agricultural land lost to development – 3 acres per minute.

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After reading through the code, what will happen when you click run?* 1 point when run move forward while there is a pile do rem

KATRIN_1 [288]

Explanation:

I'm not exactly a master at coding, but I'm pretty sure that:

The farmer will remove dirt as long as there is a pile, then stop when the pile is done.

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2 years ago

In tropical climates, the water near the surface of the ocean remains warm throughout the year as a result of solar energy absor

mote1985 [20]

Answer:

7.07%

Explanation:

Thermal efficiency can be by definition seen as the ratio of the heat utilized by a heat engine to the total heat units in the fuel consumed.

We will determine the thermal efficiency of the given problem at the attached file.

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3 years ago

Truth table for (A+B)(B+C)

serg [7]

Answer:

A truth table is a logical expression of the given inputs specially in boolean algebra and boolean functions in computer science and digital electronics.

Explanation:

Number of variables are 3 i.e A,B and C

so the number of bits are 2^3=8

A B C A+B B+C (A+B)(B+C)

0 0 0 0 0 0

0 0 1 0 1 0

0 1 0 1 1 1

0 1 1 1 1 1

1 0 0 1 0 0

1 0 1 1 1 1

1 1 0 1 1 1

1 1 1 1 1 1

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3 years ago

There are two ingredients (A and B) that will be mixed in the reactor tank. Wait for READY signal to be on (when on, it signifie

Svet_ta [14]

Answer:

Find attached of the designed PLC

Explanation:

See the attached file for the explanation.

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3 years ago

Find the minimum diameter of a solid circular shaft if it has a maximum shear stress of 53 MPa and it is to transmit 28 kW of po

amid [387]

Answer:

d= 21.6 mm

Explanation:

Given that

P= 28 KW

τ = 53 MPa

N= 2516 RPM

We know that

$P =\dfrac{2\pi NT}{60}$

$T =\dfrac{60\times P}{2\pi N}$

By putting the values

$T =\dfrac{60\times 28\times 1000}{2\pi \times 2516}$

T=106.27 N.m

We know that for solid shaft

$\tau =\dfrac{16T}{\pi d^3}$

$53\times 10^6 =\dfrac{16\times 106.27}{\pi d^3}$

$d^3=\dfrac{16\times 106.27}{\pi \times 53\times 10^6 }$

$d=\left(\dfrac{16\times 106.27}{\pi \times 53\times 10^6 }\right)^{\frac{1}{3}}$

d= 0.0216 m

d= 21.6 mm

8 0

2 years ago