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dmitriy555 [2]
4 years ago
14

The two particles are both moving to the right. Particle 1 catches up with particle 2 and collides with it. The particles stick

together and continue on with velocity vf. Which of these statements is true?
a. vf= v2
b. vf is less than v2.
c. vf is greator than v2, but less than v1.
d. vf= v1
Physics
1 answer:
Travka [436]4 years ago
4 0

Answer:

c. vf is greator than v2, but less than v1

Explanation:

The principle of conservation of linear momentum states that when two or more bodies act upon one another, their total momentum remains constant.

In a system of colliding bodies the total momentum of the system just before the collision is the same as the total momentum just after the collision.  

Collisions in which the kinetic energy is conserved are called elastic collision.

Collisions in which the kinetic energy is not conserved are called inelastic collisions.  If the two objects stick together after the collision and move with a common velocity, the collision is said to be perfectly inelastic.

<em>The above scenario is a perfectly inelastic collision. The initial velocity of particle 1 was greater than particle 2 before collision. After collision, its velocity will reduce to a final velocity vf as it transfers some of its kinetic energy to particle 2; whereas, the velocity of particle 2 will increase to a final velocity vf as it absorbs some of the kinetic energy of particle 1.</em>

Therefore,

a. vf = v2 is wrong because vf is greater than v2

b. vf is less than v2 is wrong because vf is greater than v2

c. vf is greater than v2, but less than v1 is correct.

d. vf = v1 is wrong because vf is less than v1

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Average speed = (total distance covered) / (time to cover the distance)

-- Traveling at 40 mph for 1 hour, the distance covered is 40 miles.

-- Traveling at 60 mph for 1 hour, the distance covered is 60 miles.

-- Total distance covered = (40 miles) + (60 miles) = 100 miles

-- Total time = (1 hour) + (1 hour)  =  2 hours

-- Average speed = (100 miles) / (2 hours)

<em>Average speed = 50 miles per hour</em>

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
cluponka [151]

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3 years ago
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Car enthusiasts often lower their cars closer to the ground as a matter of style. James wants to lower his car by replacing all
Alexandra [31]

Answer:

\Delta h=0.0364\ m=3.64\ cm

Explanation:

Given:

  • change in stiffness constant of the spring on replacing the original springs, \delta k=5355\ N.m^{-1}
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  • initial length of the original car-spring before compression, l_i=12\ cm=0.12\ m
  • final length of the original car-spring after compression, l_f=8.55\ cm=0.0855\ m

So, weight of the car:

w=m.g

w=1455\times 9.81

w=14273.55\ N

<u>Now the spring constant of original spring:</u>

w=4k_o.(l_i-l_f) (since 4 springs are in parallel)

14273.55=4k_o\times (0.12-0.0855)

k_o=103431.522\ N.m^{-1}

<u>So the stiffness constant of the new springs:</u>

k_n=k_o-\delta k

k_n=103431.522-5355

k_n=98076.522\ N.m^{-1}

<u>Now the height lowered:</u>

w=k_n.4\Delta h (since 4 springs are in parallel)

14273.55=4\times98076.522\times \Delta h

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Explanation:

This is simple.

Convert the speed of 45km/h to metres per second (m/s):

45 * 1000m = 45000m per hour.

1 hour = 60 seconds * 60 minutes = 3600 seconds.

45000m/h / 3600 = 12.5m/s

(A quicker way is just to divide by 3.6)

So in 20 seconds it would cover:

12.5m/s * 20s = 250m.

A car travelling at 45km/h would travel 250 metres in 20s.

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