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Liula [17]
4 years ago
6

When linolenic acid reacts with hydrogen to form a saturated fatty acid, indicate the stoichiometry of the reaction and the prod

uct that is formed. If the stoichiometry of H2 or the product is not integral, enter a fraction (i.e. 3/2).
Chemistry
1 answer:
amid [387]4 years ago
3 0

Answer : The product formed by the given reaction is, oleic acid.

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.

The coefficient tell us about that how many molecules or atoms present in the chemical equation.

When linolenic acid reacts with hydrogen then it react to form a saturated fatty acid that is oleic acid.

The balanced chemical reaction will be:

C_{18}H_{30}O_2+2H_2\rightarrow C_{18}H_{34}O_2

By the stoichiometry we can say that, 1 mole of linolenic acid reacts with 2 moles of hydrogen then it react to give 1 mole of oleic acid.

Hence, the product formed by the given reaction is, oleic acid.

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These biological compounds are nonpolar and insoluble in water:
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Read 2 more answers
A solution is made using 200.0 mL of methanol (density 0.792 g/mL) and 985.1 mL of water (density 1.000 g/mL). What is the mass
DaniilM [7]

<u>Answer:</u> The mass percent of methanol in solution is 13.85 %

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

  • <u>For water:</u>

Density of water = 1.000 g/mL

Volume of water = 985.1 mL

Putting values in above equation, we get:

1.000g/mL=\frac{\text{Mass of water}}{985.1mL}\\\\\text{Mass of water}=(1.000g/mL\times 985.1mL)=985.1g

  • <u>For methanol:</u>

Density of methanol = 0.792 g/mL

Volume of methanol = 200.0 mL

Putting values in above equation, we get:

0.792g/mL=\frac{\text{Mass of methanol}}{200.0mL}\\\\\text{Mass of methanol}=(0.792g/mL\times 200.0mL)=158.4g

To calculate the mass percent of methanol, we use the equation:

\text{Mass percent of methanol}=\frac{\text{Mass of methanol}}{\text{Mass of solution}}\times 100

Mass of solution = [158.4 + 985.1] g = 1143.5 g

Mass of methanol = 158.4 g

Putting values in above equation, we get:

\text{Mass percent of methanol}=\frac{158.4g}{1143.5g}\times 100=13.85\%

Hence, the mass percent of methanol in solution is 13.85 %

3 0
3 years ago
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