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3 years ago

1. In cognitive therapy, a therapist pays attention to the patient’s perception,___,reason, attention, and judgment.

Physics

1 answer:

barxatty [35]3 years ago

3 0

Try choosing the word Judgement for your answer, a therapist pays attention to the patient's perception, and judgment.

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The rate at which an object moves

sergejj [24]

The rate at which an object moves is called speed or velocity depending if the direction does or doesnt matter

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3 years ago

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A plant dying after being exposed to poison represents a physical change.

Sphinxa [80]

Answer:

False is the correct answer.

It is considered more of a chemical change because all of the cells inside the plant decompose (change chemicaly)

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3 years ago

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A physics student shoves a 0.50-kg block from the bottom of a frictionless 30.0° inclined plane. The student performs 4.0 j of w

Musya8 [376]

Answer:1.63 m

Explanation:

Given

mass of block $m=0.5 kg$

inclination $\theta =30^{\circ}$

Amount of work done $W=4 J$

block slides a distance s along the Plane

Work done =change in Potential Energy

Increase in height of block is $s\sin \theta$

Change in Potential Energy $=mg(\sin \theta -0)$

$\Delta P.E.=0.5\times 9.8\times s\sin 30$

$4=0.5\times 9.8\times s\sin 30$

$s=\frac{4}{2.45}$

$s=1.63 m$

5 0

3 years ago

A 30 kg dog runs at a speed of 15<br> What is the dog's kinetic energy?

sattari [20]

Ke= 1/2 mv ^ 2
15x 15 = 225
225 x 30 = 6750
6750/2 = 3375 J
Ke = 3375 J

3 0

3 years ago

If a 40 kg gymnast and a 400 kg sumo wrestler each dropped from 1 m above the trampoline, find the final position of each athlet

Tomtit [17]

When you drop an object from some height on the spring objects initial potential energy is converted to kinetic energy, this kinetic energy is then used to compress the spring. Once all the energy is used the spring stops compressing and starts oscillating.
We need to find how much the spring compressed in both cases.
From the above analysis, we can conclude that potential energy in the gravitational field has to be equal to the potential energy of compressed spring.
$mgh=\frac{1}{2}kx^2$
We solve for x (in our case h=1):
$mg=\frac{1}{2}kx^2\\
x^2=\frac{2mg}{k}\\
x=\sqrt{\frac{2mg}{k}}$
Now we just have to plug in the numbers:
$$$Sumo\ wrestler(m=400kg):x=\sqrt{\frac{2mg}{k}}=0.81m\\
$
$$$ Gymnast(m=40kg):x=\sqrt{\frac{2mg}{k}}=0.26m\\$

8 0

3 years ago