Answer:
The minimum speed = 
Explanation:
The minimum speed that the rocket must have for it to escape into space is called its escape velocity. If the speed is not attained, the gravitational pull of the planet would pull down the rocket back to its surface. Thus the launch would not be successful.
The minimum speed can be determined by;
Escape velocity = 
where: G is the universal gravitational constant, M is the mass of the planet X, and R is its radius.
If the appropriate values of the variables are substituted into the expression, the value of the minimum speed required can be determined.
Answer:
electromagnetic waves only
Explanation:
I just took the test, Hope it helps!
Answer:
a) t= 4.81 s,and t= 23.51.
b)d=6.88 m
c)v=4.8 m/s
Explanation:
Acceleration of train ,a= 0.6 m/s²
u = 0 m/s
Your speed ,V= 8.5 m/s
Lets take after t time he you catch the train
Distance travel by train in t time
----------1
d= V ( t- 4)
d= 8.5 ( t- 4) --------2
By equating equation 1 and 2
0.3 t² = 8.5 ( t- 4)
0.3 t² -8.5 t + 34 = 0
t= 4.81 s and t= 23.51
It means that you will catch train after t= 4.81 s,and t= 23.51.
t=23.51 sec means that you will catch the train after 23.51 sec also because acceleration of train is low.
Distance travel
d= 8.5 ( t- 4)
t= 4.81 s
d= 8.5 ( 4.81- 4) m
d=6.88 m
Lets speed = v
0.3 t² = v ( t- 4)
0.3 t² - v t + 4 v = 0
To have one solution

D= 0 Should be zero.
v²- 4 x 0.3 x 4 v
v = 4 x 0.3 x 4
v=4.8 m/s
4.65 × 10⁴ Joules of heat is released upon converting one mole of steam to water.

<h3>Further explanation</h3>
Specific Heat Capacity is the amount of energy needed to raise temperature of 1 kg body for 1°C.

<em>Q = Energy ( Joule )</em>
<em>m = Mass ( kg ) </em>
<em>c = Specific Heat Capacity ( J / kg°C ) </em>
<em>Δt = Change In Temperature ( °C )</em>
Let us now tackle the problem!

<u>Given:</u>
initial temperature of steam = t = 100.0°C
specific heat capacity of water = c = 4.186 J/gK
mass of steam = m = 18.0 gram
final temperature of water = t' = 25.0°C
specific latent heat of vaporization of water = Lv = 2268 J/g
<u>Asked:</u>
heat released = Q = ?
<u>Solution:</u>
![\boxed {\large {\texttt{steam 100}^oC \overset{[Q_1]}{\rightarrow} \texttt{water 100}^oC \overset{[Q_2]}{\rightarrow} \texttt{water 25}^oC}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Clarge%20%7B%5Ctexttt%7Bsteam%20100%7D%5EoC%20%5Coverset%7B%5BQ_1%5D%7D%7B%5Crightarrow%7D%20%5Ctexttt%7Bwater%20100%7D%5EoC%20%5Coverset%7B%5BQ_2%5D%7D%7B%5Crightarrow%7D%20%5Ctexttt%7Bwater%2025%7D%5EoC%7D%7D)







<h3>Learn more</h3>

<h3>Answer details </h3>
Grade: College
Subject: Physics
Chapter: Thermal Physics

Keywords: Heat , Temperature , Block , Aluminium , Ice , Cold , Water