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1 year ago

Unit Test Review

Physics

1 answer:

PolarNik [594]1 year ago

4 0

Answer:

option B...

they represent different concept...

i hope this will answer your question

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A material used for electrical wiring must have

lapo4ka [179]

A certain amount of Conductivity

5 0

2 years ago

What does the n stand for? Is it north?

Aleksandr [31]

That would be newton's. You'll be studying or have studied about newton's laws of physics. Both will help you. Hope this helps!

4 0

3 years ago

A 16 kg mass suspended from a light spring is replaced by a 4 kg mass. What factor changes the frequency of the oscillation? (a)

AnnZ [28]

Answer:

Frequency change by a factor of 2.

(b) is correct option.

Explanation:

Given that,

Mass = 16 kg

Replaced mass = 4 kg

We need to calculate the frequency

Using formula of frequency

$f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

Put the value into the formula

$f_{1}=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{16}}$

$f_{1}=\dfrac{1}{2\pi}\dfrac{\sqrt{k}}{4}}$ ....(I)

$f_{2}=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{4}}$

$f_{2}=\dfrac{1}{2\pi}\dfrac{\sqrt{k}}{2}}$ ...(II)

$f_{2}=2f_{1}$

Hence, Frequency change by a factor of 2.

5 0

3 years ago

If you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out. This happens

amm1812

Answer:

True

Explanation:

If we swing a bucket of water fast enough in a vertical circle the water does not spill out even at the top-most position of the bucket. This happens because the centrifugal force acting away from the center in a circular motion neutralizes or overcomes the gravitational force on the water particles.

<u>Centrifugal force is mathematically related as:</u>

$F=m.r.\omega^2$

where:

m = mass of the revolving body

r = radius of revolution

$\omega=$ angular velocity in radians per second

This force F acts in radially outward direction.

3 0

3 years ago

A 60-turn coil has a diameter of 13 cm. The coil is placed in a spatially uniform magnetic field of magnitude 0.60 T so that the

kramer

Answer:

a) 0.5985 V

b) 0.05985 V

c) 0.00684 V

Explanation:

Given that

Number of turn in the coil, N = 60 turns

Magnetic field of the coil, B = 0.6 T

Diameter of the coil, d = 0.13 m

If area is given as, πd²/4, then

A = π * 0.13² * 1/4

A = 0.0133 m²

The induced emf, ε = -N(dΦ*m) /dt

Note, Φm = BA

Substituting for Φ, we have

ε = -NBA/t.

Now, we substitute for numbers in the equation

ε = -(60 * 0.6 * 0.0133)/0.8

ε = 0.4788/0.8

ε = 0.5985 V

at 8s,

ε = -(60 * 0.6 * 0.0132)/8

ε = 0.4788/8

ε = 0.05985 V

at 70s

ε = -(60 * 0.6 * 0.0132)/70

ε = 0.4788/70

ε = 0.00684 V

8 0

3 years ago