The solution would be like this for this specific problem:
First, we need to write
out the balanced reaction equation for the problem:<span>
"gaseous nitrogen with gaseous hydrogen to produce
gaseous ammonia"
gaseous nitrogen + gaseous hydrogen = gaseous ammonia
gaseous nitrogen = N2(g)
gaseous hydrogen = H2(g)
gaseous ammonia = NH3(g)
In here, I’m going to show you how to balance this from start
to finish:
N2(g) + H2(g) ↔ NH3(g) (basic, unbalanced equation that shows
reactants and product)
N2(g) + H2(g) ↔ 2NH3(g) (balances the nitrogens)
N2(g) + 3H2(g) ↔ 2NH3(g) (balances the hydrogens) =>
Balanced Equation
<span>Next, we write the Keq expression of the balanced reaction:
Keq = (∏[products]^n) /(∏[reactants]^n)
Keq = [NH3]^2 / [[N2][H2]]^3
Therefore, the correct
equilibrium constant expression is Keq = (NH3)2 / (N2)(H2)3.</span></span>
Answer:
If we have more protons in the nucleus, then they hold it tighter
It provides a source of variety and differences because asexual reproduction creates exact copies or clones
I’m not quite sure but it’d probably be solar panels
Moles of K = 32.4/39 = 0.83 mole. According to stoichiometry, 2 moles of K produces 1mole of H2. Therefore, 0.83 mole of K produces = 0.83/2 = 0.415 moles of H2. Therefore number molecules of H2 = moles of H2 x 6.02 x 10^23 = 2.4983 x 10^23 molecules. Hope this helps!