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2 years ago

How does scale influence the physical and chemical properties of a substance

1 answer:

7 0

I doubt that the physical properties will be affected, however, the chemical properties will be affected especially reaction rates

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In a simple machine, the energy input is 120 J. If the efficiency of the machine is 80%, calculate the energy output

pashok25 [27]

Answer:

<h2>96 Joules</h2>

Explanation:

We know that efficiency is the ratio of output power by input power. i.e. Efficiency describes the quality of machine or system how good it is.

Solution,

Energy input of system = 120 J

Efficiency = 80% = $\frac{80}{100} = 0.8$

Now,

According to definition,

Efficiency = $\frac{output}{input}$

Cross multiplication:

$output \: = \: 0.8 \times 120$

Calculate the product

$output \: = 96 \: joules$

Hope this helps...

Good luck on your assignment...

4 0

2 years ago

A magnetic compass is placed near an insulated copper wire. When the wire is connected to a battery and a current is created, th

Luba_88 [7]

4

Every current through a wire produced a magnetic field. And since the magnetic field of Earth is weak, it will get attracted towards the wire.

4 0

2 years ago

Read 2 more answers

On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini

irinina [24]

Answer:

$v_a=0.8176 m/s$

$\Delta K=0.07969 J - 0.0849 J = -0.00521 J$

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being $m_a$ and $m_b$ the masses of pucks a and b respectively, the initial momentum of the system is

$M_1=m_av_a+m_bv_b$

Since b is initially at rest

$M_1=m_av_a$

After the collision and being $v'_a$ and $v'_b$ the respective velocities, the total momentum is

$M_2=m_av'_a+m_bv'_b$

Both momentums are equal, thus

$m_av_a=m_av'_a+m_bv'_b$

Solving for $v_a$

$v_a=\frac{m_av'_a+m_bv'_b}{m_a}$

$v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}$

$v_a=0.8176 m/s$

The initial kinetic energy can be found as (provided puck b is at rest)

$K_1=\frac{1}{2}m_av_a^2$

$K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J$

The final kinetic energy is

$K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2$

$K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J$

The change of kinetic energy is

$\Delta K=0.07969 J - 0.0849 J = -0.00521 J$

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2 years ago

A person starts at a position of 16 meters and finishes at a position of

DochEvi [55]

Answer:

38 is a good girl and a great place to work for u and I miss you y and I miss you much love your love and love to

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2 years ago

describes how the color and texture of a surface affect absorption and reflection of solar radiation?

Wewaii [24]

Most of the radiation, however, is absorbed by the earth's surface. ... Every surface on earth absorbs and reflects energy at varying degrees, based on its color and texture. Dark-colored objects absorb more visible radiation; light-colored objects reflect more visible radiation.

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2 years ago