D. Jupiter has the highest amount of gravity in our solar system
Answer:
Not possible
Explanation:
Unless there's some extra external force to keep both particles at rest after the collision, the momentum must be conserved before and after the collision.
So before the collision, 1 particle is at rest, 1 not -> total momentum is non-zero
After the collision, both particles are at rest -> total momentum is zero which is different from before.
Therefore this is not possible.
We know, Potential Energy = Force * Height
Here, F = 40 N
h = 5 m
Substitute their values,
U = 40 * 5
U = 200 J
In short, Your Answer would be Option A
Hope this helps!
Answer:
Magnetic field, B = 0.275 T
Explanation:
Given that,
Length of the wire, L = 35 cm = 0.35 m
Current carried in the wire, I = 2.6 A
The segment makes an angle of 53∘ with the direction of the magnetic field, 
Magnetic force, F = 0.2 N
To find,
The magnitude of the magnetic field.
Solution,
The magnetic force acting on the wire is given by :

is the angle between the length of wire and the magnetic field.

B = 0.275 T
Therefore, the magnitude of the magnetic field is 0.275 T. Hence, this is the required solution.
The angular acceleration of the potter's wheel is 0.067 rad/s².
The given parameters:
- Final angular speed, ωf = 0.4 rev/s
- Time of motion, t = 37.5 s
<h3>What is angular acceleration?</h3>
- Angular acceleration of an object is the rate of change of angular speed of the object.
The angular acceleration of the potter's wheel is calculated as follows;

Thus, the angular acceleration of the potter's wheel is 0.067 rad/s².
Learn more about angular acceleration here: brainly.com/question/25129606