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mafiozo [28]
4 years ago
9

Does the earth have an electric field

Physics
1 answer:
k0ka [10]4 years ago
4 0

Answer:

Yes,earth has an electric field

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Define average atomic mass and explain how it is calculated
Flauer [41]

Answer:

The average atomic mass of an element is the sum of masses of it's isotopes

Each are multiplied by it's natural abundance

Explanation:

The average atomic mass of an element is the sum of masses of it's isotopes

Each are multiplied by it's natural abundance

7 0
3 years ago
Pls help waves for physics
djverab [1.8K]

Answer:

b) 252 Hz or 260 Hz

c) 0.25 s

Explanation:

b) The frequency of the beats is 4 Hz, and one tuning fork has a frequency of 256 Hz.  Therefore, the second tuning fork is either 4 Hz lower or 4 Hz higher.

f = 252 Hz or 260 Hz

c) Period is the inverse of frequency.

T = 1/f

T = 1 / (4 Hz)

T = 0.25 s

8 0
3 years ago
How would you describe a solution?
liberstina [14]

Answer: A solution is the end of a task.

Explanation:

4 0
3 years ago
Complete this sentence. The melting point of a sample will ____________ when the size of the sample increases. (3 points)
ohaa [14]

Answer:

Answer is Option 1. decreases

8 0
3 years ago
Read 2 more answers
A uniform solid disk of radius 1.60 m and mass 2.30 kg rolls without slipping to the bottom of an inclined plane. If the angular
bagirrra123 [75]

To solve this problem we will use the concepts related to energy conservation. Both potential energy, such as rotational and linear kinetic energy, must be conserved, and the gain in kinetic energy must be proportional to the loss in potential energy and vice versa. This is mathematically

PE = KE_{lineal} + KE_{rotational}

mgh = \frac{1}{2}mv^2 +\frac{1}{2} I\omega^2

Where,

m = mass

v = Tangential Velocity

\omega = Angular velocity

I = Moment of Inertia

g = Gravity

Replacing the value of Inertia in a Disk and rearranging to find h, we have

mgh = \frac{1}{2}mv^2 +\frac{1}{2} I\omega^2

mgh = \frac{1}{2}mr^2\omega^2 + \frac{1}{2}(\frac{1}{2}mr^2)\omega^2 )

h = \frac{3}{4} \frac{r^2\omega^2}{g}

Replacing,

h = \frac{3}{4} \frac{(1.6)^2 (5.35)^2}{9.8}

h = 5.607m

Therefore the height of the inclined plane is 5.6m

3 0
4 years ago
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