Answer:
Convective zone, chromosphere, corona
Explanation:
A star like the Sun is divided into different layers according to pressure, density, temperature, and the mechanics of energy transport (in the case of the convective zone and radiative zone) for each of those layers.
In stars, there is an equilibrium between two forces, the force of gravity in the inward direction due to their own mass and the radiation pressure in the upward direction as a consequence of the nuclear reaction in their core, that is known as hydrostatic equilibrium.
That leads to different layers according with the properties described above.
Near the core, in the Sun, there is a radiative zone since radiation is the best mechanism of energy transport in this area. Then, in the next layer, it can be found that convection becomes a more efficient way of energy transport that radiation due to the fact that the inner part of the convection zone is at a greater temperature than the outer one.
Finally, there is the atmosphere of the Sun (chromosphere, photosphere, and corona).
Key terms:
Convection: Transport of energy due to different in density and temperature of a material (liquid, gas).
Carrying capacity is the maximum amount of individuals a space can hold.
Answer:
-0.105 m/s
Explanation:
Given that
Mass of the astronaut, m(a) = 68.5 kg
Mass of the tool, m(t) = 2.25 kg
Speed of the tool after it is thrown, v(t) = 3.20 m/s
We know that momentum of a particle,
p = mv
See the attachment for calculations
Therefore, the speed is 0.105 m/s and it moves in the opposite direction.
Answer:
The time interval during which the rocket engine provides upward acceleration is 2.1 s
Explanation:
The equations for the height of the rocket are as follows:
y = y0 + v0 · t + 1/2 · a · t²
and, after the engine burnout:
y = y0 + v0 · t + 1/2 · g · t²
Where:
y = height of the rocket at time t
y0 = initial height
v0 = initial velocity
t = time
a = upward acceleration
g = acceleration due to gravity (downward)
The velocity of the rockey is given by this equation:
v = v0 + a · t (v0 = 0 because the rocket is launched from rest)
v = a · t
and after burnout:
v = v0 + g · t
Where v = velocity at time t
We know that when the altitude is 64 m the velocity is 60 m/s. Then let´s use the following equation system:
y = y0 + v0 · t + 1/2 · a · t² (y0 and v0 = 0)
v = a · t
Then:
64 m = 1/2 · a · t²
60 m/s = a · t
a = 60 m/s / t
Replacing "a = 60m/s / t" in the equation of height:
64 m = 1/2 ·( 60m/s / t) · t²
64 m = 30 m/s · t
t = 64 m / 30 m/s
t = 2.1 s
Then, the time interval during which the rocket engine provides upward acceleration is 2.1 s
