The molarity of the resulting solution obtained by diluting the stock solution is 3 M
<h3>Data obtained from the question </h3>
- Molarity of stock solution (M₁) = 15 M
- Volume of stock solution (V₁) = 500 mL
- Volume of diluted solution (V₂) = 2.5 L = 2.5 × 1000 = 2500 mL
- Molarity of diluted solution (M₂) =?
<h3>How to determine the molarity of diluted solution </h3>
M₁V₁ = M₂V₂
15 × 500 = M₂ × 2500
7500 = M₂ × 2500
Divide both side by 2500
M₂ = 7500 / 2500
M₂ = 3 M
Thus, the volume of the resulting solution is 3 M
Learn more about dilution:
brainly.com/question/15022582
#SPJ1
Answer:
Be,Mg,Ra etc
Explanation:
It should be palced in group 2A because as it reacts with chlorine in ratio of 1:2 . It's valancy is 2 and is metal as it react with non metal donating two electrons .
one more thing it fits there orderly
Answer:
Mole fraction for C₂₂H₁₉Cl₂NO₃ = 0.0086
Explanation:
Mole fraction remains a sort of concentration. It indicates:
moles of solute / (moles of solute + moles of solvent)
Moles of solute / Total moles.
Solute: Cypermethrin → C₂₂H₁₉Cl₂NO₃
Solvent: Water (PM = 18g/mol)
We calculate moles from solvent: 1000g /18 g/mol = 55.5 moles
We calculate PM for C₂₂H₁₉Cl₂NO₃
12g/mol . 22 + 1g/mol . 19 + 35.45 g/mol . 2+ 14g/mol + 16g/mol . 3 = 416 g/m
Moles of solute: 200 g / 416g/mol = 0.481 moles
Total moles: 0.481 + 55.5 = 55.98 moles
Mole fraction for C₂₂H₁₉Cl₂NO₃ = 0.481 moles / 55.98 moles = 0.0086
Answer:
wavelength = 6×10⁻⁷m
f = 0.5 ×10¹⁵ Hz
Explanation:
Given data:
Energy of photon = 3.2×10⁻¹⁹ J
Wavelength of photon = ?
Frequency of photon = ?
Solution:
E = h.f
f = frequency
h = planck's constant
E = energy
f = E/h
f = 3.2×10⁻¹⁹ Kg.m².s⁻²/ 6.63×10⁻³⁴ m².Kg/s
f = 0.5 ×10¹⁵ s⁻¹
s⁻¹ = Hz
f = 0.5 ×10¹⁵ Hz
Wavelength:
speed of light = wavelength × frequency
wavelength = speed of light / frequency
wavelength = 3×10⁸ m.s⁻¹ /0.5 ×10¹⁵s⁻¹
wavelength = 6×10⁻⁷m
Answer:
Explanation:
From similar question, equation (b) is
Molecular Equation:
- Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s)
Net Ionic Equation:
- Cu(s) + 2Ag⁺(aq) → Cu²⁺(aq) + 2Ag(s)
<u>1. Mole ratio:</u>
<u>2. Convert 1.147 g of Cu(s) to moles:</u>
- Atomic mass of Cu: 63.546g/mol
- Number of moles = mass in grams / atomic mass
- Number of moles = 1.147 g / 63.546 g/mol = 0.01805 mol Cu(s)
<u />
<u>3. Calculate the moles of Ag(s):</u>
<u />
<u>4. Convert 0.03610 mol Ag(s) to grams:</u>
- Atomic mass of Ag(s) = 107.868g/mol
- Mass = 0.03610mol × 107.868g/mol = 3.894g
