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Feliz [49]
3 years ago
12

As a rocket is accelerating vertically upward at 92 m/s^2 near the Earth's surface, it releases a projectile. Immediately after

release the acceleration (in m/s^2) of the projectile is: A) 9.8 down. B) 9.8 up C) 9.2 down D) 92 up E) none of the above
Physics
1 answer:
valkas [14]3 years ago
6 0

Answer:

A)

Explanation:

Once released, the projectile is subject only to the influence of gravity, which is always downward, and produces on the object an acceleration of 9.8 m/s².

The vertical acceleration of the rocket only supplies an initial velocity to the projectile, in the vertical direction, upwards.

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The mass of the skateboard is 1.8kg and the mass of the skateboarder is 42kg.
Murljashka [212]
Total momentum must be conserved since there are no external forces in the horizontal direction on the skateboarder or the skateboard.

Momentum before the jump:
P = m_1v_1 + m_2v_2 = (1.8kg)(0) + (42kg)(0) = 0

Momentum after the jump:
P =  m_1v_1 + m_2v_2 = (1.8kg)(v_1) + (42kg)(0.3 \frac{m}{s} ) = 0

Solving for the velocity v:
v_1 = -  \frac{m_2v_2}{m_1}  = -  \frac{(42kg)(0.3 \frac{m}{s} )}{1.8kg} = -7  \frac{m}{s}
4 0
4 years ago
A passengers train travels from reno to Las Vegas a distance of 706 km in 6.5 h. what is the change average speed?
12345 [234]

Answer: learn how to do it on your own idiot

Explanation: try hard in school

8 0
3 years ago
block of mass m sits at rest on a rough inclined ramp that makes an angle with the horizontal. What must be true about normal fo
oee [108]

Answer:

Explanation:

For a body on a ramp with mass m, the forces acting on the body along the vertical component are the weight and the normal reaction.

The weight of the body acts in the negative y direction while the normal reaction acts in the positive y direction

Taking the sum of forces along the y component

Sum Fy = -W+R = ma

Since acceleration is zero

-W+R = m(0)

-W+R = 0

-W = -R

W = R

Hence the Normal reaction force acting on the on the body is equal to normal force

6 0
3 years ago
A student stretches a spring, attaches a 1.20 kg mass to it, and releases the mass from rest on a frictionless surface. The resu
Sphinxa [80]

Answer:

the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Explanation:

Given that;

mass of the object m = 1.20 kg

period of oscillation = 0.750 s

Amplitude ( A/x) = 15.0 cm = 0.15 m

now;

a) Determine the oscillation frequency;

oscillation frequency f = 1/T

we substitute

f = 1 / 0.750 s

f = 1.33 Hz

Therefore, the oscillation frequency is 1.33 Hz

b) Determine the spring constant;

we solve for spring constant from the following expression;

T = 2π√(m/k)

k = 4π²m / T²

so we substitute

k = (4π² × 1.20) / (0.750)²

k = 47.3741 / 0.5625

k =  84.22 N/m

Therefore, the spring constant is 84.22 N/m

c) determine the speed of the mass when it is halfway to the equilibrium position

So, at equilibrium, the energy is equal to K.E

such that;

1/2mv² = 1/2kx²

mv² = kx²

v² = kx² / m

v = √( kx²/m)

we substitute

v = √( 84.22×(0.15 m)²/ 1.2 )

v = √( 1.89495 / 1.2 )

v = √ 1.579125

v = 1.26 m/s  

Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

3 0
3 years ago
What came first the chicken or the egg
maxonik [38]

Answer:

The Egg

Explanation:

personally the Chicken who would lay the egg would have to come from an Egg itself, then It would have to grow up and then Produce an egg that will produce a chicken and so on.

6 0
3 years ago
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