Answer:
<u><em>3.721 m/s</em></u>
This is the explanation of the ans
A 5.0\, \text {kg}5.0kg5, point, 0, start text, k, g, end text box is at rest on a table. The static friction coefficient \mu_sμ
2 answers:
Answer:
25 N
Explanation:
When a force is applied to an object, for it to move it has to overcome the frictional force. The frictional force is perpendicular to the surface on which it acts. For an object at rest, it is acted upon by static friction, this friction must be overcome before the object can move, while a moving object is resisted by kinetic friction that prevents it from moving.
Since the box is at rest, it is acted upon by a static friction.
mass = 5 kg, acceleration due to gravity = 10 m/s², static friction coefficient = 0.5
Weight of the box = mass * acceleration due to gravity = 5 * 10 = 50 N
The applied horizontal force (F) is:
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Answer:
B = 62.9 N
Explanation:
This is an exercise on Archimedes' principle, where the thrust force equals the weight of the liquid
B = ρ g V
write the equilibrium equation
T + B -W = 0
B = W- T (1)
use the density to write the weight
ρ = m / V
m = ρ V
W = ρ g V
substitute in 1
B = m g -T
B = g V - T
To finish the calculation, the density of the material must be known, suppose it is steel \rho_{body} = 7850 kg / m³
calculate
B = 7850 9.8 1.20 10⁻³ - 29.4
B = 92.3 - 29.4
B = 62.9 N
Answer:
force = 1 × N
Explanation:
given data
automobile mass = 1200 kg
insect mass = 0.0001 kg
insect accelerated = 100 m/s²
to find out
magnitude of the force the insect exerts on the car
solution
we get here force the insect exerts that is express as
force = mass × acceleration ............1
put here value we get
force = 0.0001 × 100 m/s²
force = 1 × N