Answer:
the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
Explanation:
Given the data in the question;
Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J
Mass of proton = 1.673 × 10⁻²⁷ kg
Charge of proton = 1.602 × 10⁻¹⁹ C
distance d = 2 m
we know that
Kinetic Energy = Charge of proton × Potential difference ΔV
so
Potential difference ΔV = Kinetic Energy / Charge of proton
we substitute
Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )
Potential difference ΔV = 20287.14 V
Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;
E = Potential difference ΔV / distance d
we substitute
E = 20287.14 V / 2 m
E = 10143.57 V/m or 1.01 × 10⁴ V/m
Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
Answer:
Calcium bromide is the name for compounds with the chemical formula CaBr2(H2O)x.
The correct answer for this would be "A car traveling the speed limit" this is because the car is not accelerating, and all the other answers are wrong because the objects in those are accelerating <span />
Answer:
The ball has a potential energy of 53 J.
Explanation:
Mechanical energy, E = Kinetic energy + Potential energy
E = K.E + P.E
65 = 12 + P.E
P.E = 65 – 12
P.E = 53 J
Therefore the potential energy of the ball is 53 J
Answer: 13.6 N
Explanation:
The equation of motion for the rabbit is:
(1)
Where:
is the distance traveled by the rabbit
is the rabbit's initial velocity, assuming it started from rest
is the time
is the acceleration
Isolating :
(2)
(3)
(4)
On the other hand, the force 
is given by:
(5)
Where 
is the mass of the rabbit
Substituting (4) in (5):
(6)
Finally:
