Answer:
4
Explanation:
There are 4 significant figures because when there is not a decimal, then only numerical values over 0 are counted. So the numbers counted in sig figs are 2049, and none of the other 0s.
So if it was 204,900,000,000.0, then it would have 12 significant figures.
2,8,8
this is the standard shell pattern..
this ok?
Energy, in a form of gamma rays, is <span>released when an electron and its antiparticle (positron) annihilate each other. </span>
Answer:
![C_m=0.474\frac{J}{g\°C}](https://tex.z-dn.net/?f=C_m%3D0.474%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D)
Explanation:
Hello.
In this case, since this is a system in which the water is heated up and the metal is cooled down in a calorimeter which is not affected by the heat lose-gain process, we can infer that the heat lost by the metal is gained be water, it means that we can write:
![Q_m=-Q_w](https://tex.z-dn.net/?f=Q_m%3D-Q_w)
Thus, in terms of masses, specific heats and temperatures we can write:
![m_mC_m(T_{eq}-T_m)=-m_wC_w(T_{eq}-T_w)](https://tex.z-dn.net/?f=m_mC_m%28T_%7Beq%7D-T_m%29%3D-m_wC_w%28T_%7Beq%7D-T_w%29)
Whereas the equilibrium temperature is the given final temperature of 28.4 °C and we can compute the specific heat of the metal as shown below:
![C_m=\frac{-m_wC_w(T_{eq}-T_w)}{m_m(T_{eq}-T_m)}](https://tex.z-dn.net/?f=C_m%3D%5Cfrac%7B-m_wC_w%28T_%7Beq%7D-T_w%29%7D%7Bm_m%28T_%7Beq%7D-T_m%29%7D)
Plugging the values in and since the density of water is 1.00 g/mL so the mass is 80.0g, we obtain:
![C_m=\frac{-80.0g*4.184\frac{J}{g\°C} (28.4\°C-24.0\°C)}{44.0g(28.4\°C-99.0\°C)}\\\\C_m=0.474\frac{J}{g\°C}](https://tex.z-dn.net/?f=C_m%3D%5Cfrac%7B-80.0g%2A4.184%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%20%2828.4%5C%C2%B0C-24.0%5C%C2%B0C%29%7D%7B44.0g%2828.4%5C%C2%B0C-99.0%5C%C2%B0C%29%7D%5C%5C%5C%5CC_m%3D0.474%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D)
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