All categories

3 years ago

How many grams are in 5.4 moles of K2SO4

Chemistry

1 answer:

Vikentia [17]3 years ago

3 0

Answer:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles K2SO4, or 174.2592 grams.

Explanation:

You might be interested in

How many grams are there in 2.3*10^24 atoms of silver nitrate ?

Paul [167]

410g Ag

2.3*10^24 atoms

1 molcule Ag- 6.02g*10^3

6 0

3 years ago

Which of the following would have the largest amount of mass?

Elodia [21]

Answer:

1 kg

Explanation:

prefix nano means 10^-9

kilo 10^3

mili 10^-3

centi 10^-2

the largest amount is 1 kg

7 0

3 years ago

Read 2 more answers

It’s and emergency! PLEASE HELP!

ki77a [65]

Answer:

We'll have 82 moles ZnO and 41 moles S

Explanation:

Step 1: data given

Number of moles Zinc (Zn) = 82 moles

Number of moles sulfur oxide (SO2) = 42 moles

Step 2: The balanced equation

2Zn + SO2 → 2ZnO + S

Step 3: Calculate the limiting reactant

For 2 moles Zinc we need 1 mol sulfur oxide to produce 2 moles zinc oxide and 1 mol sulfur

Zinc is the limiting reactant. It will completely be consume (82 moles). Sulfur oxide is in excess. There will react 82/2 = 41 moles

There will remain 42-41 = 1 mol SO2

Step 4: Calculate moles of products

For 2 moles Zinc we need 1 mol sulfur oxide to produce 2 moles zinc oxide and 1 mol sulfur

For 82 moles Zinc we'll have 82 moles of Zinc Oxide (ZnO)

For 82 moles Zinc we'll have 82/2 = 41 moles of sulfur

We'll have 82 moles ZnO and 41 moles S

5 0

3 years ago

What is the mass of 4.32 mol GaI3? <br> 455 g <br> 1,230 g <br> 1,720 g <br> 1,950 g

denis23 [38]

Answer:

D. 1,950 g

Explanation:

I completed the test and it is the correct answer!

8 0

3 years ago

How many grams of water are produced when 35.8 grams of Calcium hydroxide reacts with lots of Hydrochloric acid?

Veseljchak [2.6K]

Are produced 72 grams of water in this reaction.

<h3>Mole calculation</h3>

To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

$Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2$

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:

$MM_{Ca(OH)_2} = 74.1g/mol$

$MM = \frac{g}{mol}$

$74.1 = \frac{35.8}{mol}\\mol = 2$

So, if there are 2 mols of Ca(OH)2:

Ca(OH)2 | H2O

$\frac{1mol}{2mol} =\frac{2mol}{xmol}$

$x = 4mol$

Finally, just find the number of grams of water using your molar mass:

$MM_{H_2O} = 18g/mol$

$18= \frac{m}{4}\\m = 72g$

So, 72 grams are produced of water in this reaction.

Learn more about mole calculation in: brainly.com/question/2845237

5 0

2 years ago