solution:
When an uncharged conducting object brought near to a charged insulating object there is a force on the conducting object to move the electrons within it to opposite sides of the conductor. That means there is a separation of charges in the conducting object in the presence of the charged insulating object near to it but the charge on the conducting object is neutral.
Thus, the conducting object is uncharged.
There is a force of attraction between the uncharged conducting object and the insulating object when it brought near to the insulating object.
Thus, there is a force on the conducting object.
The conductor remains uncharged and a force is exerted on it.
Answer:
<em>The y component of his displacement is 11.22 meters</em>
Explanation:
<u>Components of the displacement</u>
The displacement is a vector because it has a magnitude and a direction. Let's suppose a displacement has a magnitude r and a direction θ, measured with respect to the positive x-direction. The horizontal component of the displacement is calculated by:
![x=r\cos\theta](https://tex.z-dn.net/?f=x%3Dr%5Ccos%5Ctheta)
The vertical component is calculated by:
![y=r\sin\theta](https://tex.z-dn.net/?f=y%3Dr%5Csin%5Ctheta)
The hiker has a displacement with magnitude r = 20.51 m at an angle of 33.16 degrees. Substituting in the above equation:
![y=20.51\sin(33.16^\circ)](https://tex.z-dn.net/?f=y%3D20.51%5Csin%2833.16%5E%5Ccirc%29)
![y=11.22\ m](https://tex.z-dn.net/?f=y%3D11.22%5C%20m)
The y component of his displacement is 11.22 meters
The Cat’s Gravity To The Ground And The Action Of The Cat’s Paws Pushing Back Off Of The Ground Springing It Forward.
Answer:
Analog communication systems.
Digital communication systems.
Baseband communication systems.
Carrier communication systems.
Explanation:
Answer:
5×10¯⁴ m².
Explanation:
From the question given above, the following data were obtained:
Pressure (P) = 200 N/m²
Weight = Force (F) = 0.1 N
Area (A) =?
Pressure, force and area are related by the following equation:
Pressure (P) = Force (F) / Area (A)
P = F / A
With the above formula, we can obtain the area of the coin as follow:
Pressure (P) = 200 N/m²
Weight = Force (F) = 0.1 N
Area (A) =?
P = F / A
200 = 0.1 / A
Cross multiply
200 × A = 0.1
Divide both side by 200
A = 0.1 / 200
A = 5×10¯⁴ m²
Thus, the area of the coin is 5×10¯⁴ m².