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3 years ago

Which of the following is a type of wave that travels at a right angle relative to the direction of motion?

1 answer:

kramer3 years ago

3 0

"Transverse" wave is the type of wave among the following choices given in the question that <span>travels at a right angle relative to the direction of motion. The correct option among all the options that are given in the question is the fourth option or the last option. I hope that this is the answer that has come to your help.</span>

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Buoyant force acts in the opposite direction as the force of

Natalka [10]

Buoyant force acts in the opposite direction as the force of

Gravity

3 0

3 years ago

A 500 kg sports car accelerates uniformly from rest reaching a speed of 30 m/s in 6 seconds .Find the distance travelled by the

Dimas [21]

Answer:

the distance traveled by the sports car is 90 m

Explanation:

Given;

mass of the sports car, m = 500 kg

initial velocity of the sports car, u = 0

final velocity of the sport car, v = 30 m/s

time of motion of the car, t = 6 s

The distance traveled by the sports car is calculated as;

$s = (\frac{u+v}{2} )t\\\\s = (\frac{0+30}{2} ) \times 6\\\\s = 15 \times 6\\\\s = 90 \ m$

Therefore, the distance traveled by the sports car is 90 m

6 0

3 years ago

Johanna is studying what happens to the energy as a ball rolls down a ramp. What is one form of energy that she is studying? gra

timofeeve [1]

Answer: gravitational potential energy

Explanation:

Gravitational potential energy is refered to as the potential energy that an object has due to its gravitational field, which in turn is being turned into a kinetic energy when there is a fall of such objects.

Since Johanna is studying what happens to the energy as a ball rolls down a ramp, the form of energy here is the gravitational potential energy.

3 0

3 years ago

Read 2 more answers

A parallel-plate capacitor is constructed of two square plates, size L×L, separated by distance d. The plates are given charge ±

gladu [14]

Answer:

E(final)/E(initial)=2

Explanation:

Applying the law of gauss to two parallel plates with charge density equal σ:

$E=\sigma/\epsilon_{o}=Q/(L^{2}*\epsilon_{o})\\$

So, if the charge is doubled the Electric field is doubled too

E(final)/E(initial)=2

3 0

3 years ago

An object completes one and half revolution of a circle of radius R calculate the displacement and distance

Papessa [141]

Answer:

Distance is path length covered by particle. When particle moves along half circle, it covers half the circumference therefore distance covered is (2×pi×r)/2 = pi× r. ... Hence displacement is equal to diameter or 2 times the radius of circle.

8 0

3 years ago