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ss7ja [257]
3 years ago
13

Elements in the same periodic table group have the same___

Physics
1 answer:
Aliun [14]3 years ago
6 0

Answer:

elements in the same periodic table group have the same valence electrons

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If an electric wire is allowed to produce a magnetic field no larger than that of the Earth (0.50 x 10-4 T) at a distance of 15
ser-zykov [4K]

Answer:

I = 37.5\ A

Explanation:

Given,

Magnetic field,B = 0.5 x 10⁻⁴ T

distance,r= 15 cm = 0.15 m

Current = ?

Using Ampere's law of magnetic field

B = \dfrac{\mu_0I}{2\pi r}

I= \dfrac{B (2\pi r)}{\mu_0}

I= \dfrac{0.5\times 10^{-4}\times (2\pi \times 0.15)}{4\pi \times 10^{-7}}

I = 37.5\ A

Current in the wire is equal to I = 37.5\ A

3 0
3 years ago
A guitar string is 90 cm long and has a mass of 3.7 g . The distance from the bridge to the support post is L=62cm, and the stri
zvonat [6]

To solve this problem we will apply the concept of frequency in a string from the nodes, the tension, the linear density and the length of the string, that is,

f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})

Here

n = Number of node

T = Tension

\mu = Linear density

L = Length

Replacing the values in the frequency and value of n is one for fundamental overtone

f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})

f = \frac{1}{2(62*10^{-2})}(\sqrt{\frac{500}{(\frac{3.7*10^{-3}}{90*10^{-2}})}})

\mathbf{f = 281.2Hz}

Similarly plug in 2 for n for first overtone and determine the value of frequency

f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})

f = \frac{2}{2(62*10^{-2})}(\sqrt{\frac{500}{(\frac{3.7*10^{-3}}{90*10^{-2}})}})

\mathbf{f = 562.4Hz}

Similarly plug in 3 for n for first overtone and determine the value of frequency

f = \frac{n}{2L}(\sqrt{\frac{T}{\mu}})

f = \frac{3}{2(62*10^{-2})}\bigg (\sqrt{\frac{500}{(\frac{3.7*10^{-3}}{90*10^{-2}})}} \bigg)

\mathbf{f= 843.7Hz}

4 0
3 years ago
A mass of 2000 kg. is raised 5.0 m in 10 seconds. What is the potential energy of the mass at this height?
kolbaska11 [484]

Answer:

98,000J

Explanation:

Given parameters :

Mass = 2000kg

Height = 5m

Time = 10s

P. E = mgh

P. E = 2000x 5x 9.8

P.E = 98,000J

5 0
3 years ago
A 25 pF parallel-plate capacitor with an air gap between the plates is connected to a 100 V battery. A Teflon slab (dielectric c
adoni [48]

Answer:

The change in the charge on the positve plate when the Teflon is inserted is +2.5 nC.

Explanation:

  • It can be showed that the capacitance of a parallel-plate capacitor, can be expresssed as follows:

       C = \frac{\epsilon*A}{d}

  • Where ε, is the dielectric constant of the material that fills the space between plates.
  • When this space is filled with air, ε= ε₀ = 8,85*10⁻¹² F/m.
  • At the same time, the capacitance of a capacitor, by definition, is as follows:

       C =\frac{Q}{V}

  • If we insert a Teflon slab, in such a way that fills completely the gap between the plates, all other parameters being equal, if ε = 2*ε₀, this means that C₂ = 2* C₁. = 50 pF
  • As V₂=V₁ (due to the capacitor remains connected to the same battery) the charge must be the double, so Q₂ = 2* Q₁ = 5 nC.
  • So, the change in the charge of the positive plate is +2.5 nC.
3 0
3 years ago
The average mass of a car in the US is 1.440 x 10^6 g. Express this mass in kg.
wolverine [178]

Answer:

Average mass of acar in the US (in kg) = 1440 kg

Explanation:

Average mass of a car in the US (in g) = 1.440 × 10⁶ g

Mass in kg:

\rm 1 \: g =  {10}^{ - 3}  \: kg \\  \\  \rm 1.440 \times 10^6 \ g = 1.440 \times 10^6  \times  {10}^{ - 3} \ kg \\  \\  \rm = 1.440 \times 10^{6 - 3} \ kg \\  \\  \rm = 1.440 \times 10^3 \ kg \\  \\ \rm = 1.440 \times 1000 \ kg \\  \\ \rm = 1440 \ kg

5 0
3 years ago
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