The angle of projection given that the range is 256√3 m and the maximum height reached is 64 m is 30°
<h3>Data obtained from the question</h3>
- Range (R) = 256√3 m
- Maximum height (H) = 64 m
- Acceleration due to gravity (g) = 9.8 m/s²
- Angle of projection (θ) = ?
<h3>How to determine the angle of projection</h3>
R = u²Sine(2θ) / g
256√3 = u²Sine(2θ) / 9.8
Cross multiply
256√3 × 9.8 = u²Sine(2θ)
Divide both sides by Sine(2θ)
u² = 256√3 × 9.8 / Sine(2θ)
H = u²Sine²θ / 2g
64 = [256√3 × 9.8 / Sine(2θ)] × [Sine²θ / 2 × 9.8]
64 = [256√3 / Sine(2θ)] × [Sine²θ / 2]
Recall
Sine²θ = SineθSineθ
Sine2θ = 2SineθCosθ
Thus,
64 = [256√3 / 2SineθCosθ] × [SineθSineθ / 2]
64 = 256√3 × Sineθ / 4Cosθ
Recall
Sineθ / Cosθ = Tanθ
Thus,
64 = 256√3 / 4 × Tanθ
Divide both side by 256√3 / 4
Tanθ = 64 ÷ 256√3 / 4
Tanθ = 0.5774
Take the inverse of Tan
θ = Tan⁻¹ 0.5774
θ = 30°
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Answer:
Total electric potential, 
Explanation:
It is given that,
First charge, 
Second charge, 
Distance of first charge from origin, 
Distance of second charge from origin, 
We need to find the total electric potential at the origin. The electric potential at the origin is given by :
V = 1321826.08 V
or
So, the total electric potential at the origin is 
. Hence, this is the required solution.
B. Energy is added to the cube causing particles to speed up and spread out, causing the cube to melt.
The power provided by the car battery is 4200W or 4.2kW
<u>Explanation:</u>
Given:
Voltage, V = 12V
Current, I = 350A
Power, P = ?
According to Ohm's law:
Power = voltage X current
On substituting the value we get:
P = 12 X 350
P = 4200W
Therefore, the power provided by the car battery is 4200W or 4.2kW
True I guess
because if the force is balanced and there is no net force, the object will not accelerate and the velocity will remain constant...
Not sure
