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Anit [1.1K]
2 years ago
15

The movement of substances from an area of low concentration to an area of high concentration is called what?

Chemistry
1 answer:
RUDIKE [14]2 years ago
8 0

Answer:

Diffusion

Explanation:

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A total of 20.0 mL of sodium hydroxide (NaOH) was neutralized by 30.0 mL of 0.250 M hydrogen bromide (HBr). What was the concent
Karolina [17]

Answer:

0.375 M

Explanation:

NaOH(aq) + HBr(aq) ------------> NaBr(aq) + H2O(l)

Concetration of acid CA= 0.250M

Concentration of base CB= ????

Volume of acid VA= 30.0mL

Volume of base VB= 20.0mL

Number of moles of acid nA= 1

Number of moles of base nB= 1

CA VA/CB VB= nA/nB

CB= CAVAnB/VB nA

= 0.25× 30×1/20×1= 0.375 M

8 0
3 years ago
Specify the number of protons, neutrons, and electrons in the neutral atom chromium-52
Alborosie
Its has 24 protons, 24 electrons, and 28 nuetrons

3 0
3 years ago
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How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?
Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

pH= -log[H]\\pH= -log (\frac{kw}{[OH]})

8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}

[OH]=1.69E-6

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

Cu(OH)_2 -> Cu^{2+} + 2OH^-

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

Kps= [Cu^{2+}] [OH]^2

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

Kps= s*(2s+1.69E-6)^2

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is s=4.96E-8 mol/L

Now, let us calculate the moles in 1 L:

moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles

7 0
3 years ago
Of the choices below, which is true for the relationship shown? It is Ka for the acid H3P2O72−. It is Kb for the acid H3P2O72−.
Naily [24]
The expression for the Ka for the given acid is:

Ka = [H2P2O7^2-] [H3O+] /[H3P2O7^2-]

<span>Ka is the acid dissociation constant or the acidity constant. It is a measure of the acid strength when in solution. It is an equilibrium constant for the dissociation of the acid.</span>
3 0
3 years ago
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Two basic properties of the gas phase are
Molodets [167]
The choices can be found elsewhere and as follows:

A.) a definite shape and a definite volume
B.) a definite shape but no definite volume
C.) no definite shape and no definite volume

I believe the correct answer is option C. Two basic properties of the gas phase would be it has no definite shape and no definite volume. It takes the shape and volume of its container. Hope this answers the question.
6 0
3 years ago
Read 2 more answers
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