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vovikov84 [41]
3 years ago
10

How do you solve 2A= 4lw+2Lh+6wH for w

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

Answer:

\displaystyle w=\frac{A-Lh}{2l+3H}

Explanation:

Solving Equations by Isolation

We have this equation:

2A= 4lw+2Lh+6wH

Let's solve it for w step by step. First, we flip both sides

4lw+2Lh+6wH =2A

Subtracting 2Lh in both sides

4lw+2Lh+6wH-2Lh =2A-2Lh

Simplifying

4lw+6wH =2A-2Lh

Factoring w

w(4l+6H) =2A-2Lh

Dividing by (4l+6H)

\displaystyle w=\frac{2A-2Lh}{4l+6H}

Simplifying by 2:

\displaystyle \boxed{w=\frac{A-Lh}{2l+3H}}

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The equation for potential energy is denoted as; 

Pe = mgh,

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h = (Pe)/(mg)

Plug in your given units, and solve!





Post-check:

h = Pe/mg

h = 175J/(0.36g)(-9.81m/s^2)

h = appr. 49.5 meters

Note: Potential energy is a vector quantity; the displacement of the apple will be a negative number, but the distance itself, a scalar quantity, will be the absolute value of that.
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What is the average velocity of a car if it travels from position 25m to a position of -7m in 34 seconds?
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Answer:

vp = 0.94 m/s

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Formula

Vp = position/ time

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3 years ago
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A light ray incident from medium 1 to medium 2, where n1>n2. When the incident angle exceed the critical angle ac, the refrac
vovikov84 [41]

Explanation:

(a)

Critical angle is the angle at the angle of refraction is 90°. After the critical angle, no refraction takes place.

Using Snell's law as:

n_1\times {sin\theta_i}={n_2}\times{sin\theta_r}

Where,  

{\theta_i}  is the angle of incidence

{\theta_r} is the angle of refraction = 90°

{n_2} is the refractive index of the refraction medium

{n_1} is the refractive index of the incidence medium

Thus,

n_1\times {sin\ \theta_{critical}}={n_2}\times{sin\ 90^0}

The formula for the calculation of critical angle is:

{sin\theta_{critical}}=\frac {n_2}{n_1}

Where,  

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Answer:

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