2 years ago

How do you solve 2A= 4lw+2Lh+6wH for w

Physics

1 answer:

gizmo_the_mogwai [7]2 years ago

6 0

Answer:

$\displaystyle w=\frac{A-Lh}{2l+3H}$

Explanation:

Solving Equations by Isolation

We have this equation:

$2A= 4lw+2Lh+6wH$

Let's solve it for w step by step. First, we flip both sides

$4lw+2Lh+6wH =2A$

Subtracting 2Lh in both sides

$4lw+2Lh+6wH-2Lh =2A-2Lh$

Simplifying

$4lw+6wH =2A-2Lh$

Factoring w

$w(4l+6H) =2A-2Lh$

Dividing by (4l+6H)

$\displaystyle w=\frac{2A-2Lh}{4l+6H}$

Simplifying by 2:

$\displaystyle \boxed{w=\frac{A-Lh}{2l+3H}}$

You might be interested in

Identify the number of atoms on the reactant side of the chemical equation.

klio [65]

Hi, I believe this should belongs to the chemistry section, but nevertheless here is the solution :

Number of Fe atoms: (2) + (2) =4
Number of O atoms. : (3)
Number of H atoms: (3 X 2)=6
Total atoms: 4+3+6=13 atoms

5 0

3 years ago

Read 2 more answers

Which 2 points are unbalanced??

Ganezh [65]

Answer: section 2 and 4

Explanation:

I had this problem before and that was the answer.

3 0

2 years ago

Weight is a force that depends on mass and ?

Maksim231197 [3]

Answer:

Gravitational force.

8 0

2 years ago

A stuntman is being pulled along a rough road at a constant velocity by a cable attached to a moving truck. The cable is paralle

Alex73 [517]

Answer:

715 N

Explanation:

Since the system is moving at a constant velocity, the net force must be 0. The tension on the road is equal and opposite direction with the kinetic friction force created by the road and the stuntman.

Let g = 9.8 m/s2

Gravity and equalized normal force is:

N = P = mg = 107*9.8 = 1048.6 N

Kinetic friction force and equalized tension force on the rope is

$T = F_{\mu} = N\mu = 1048.6 * 0.682 = 715.1452 N$

6 0

2 years ago

Atoms with a low ionization energy give up their outer valence electrons with

Sedbober [7]

Answer:

a. true

Explanation:

i think

that my answer

7 0

2 years ago