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vovikov84 [41]
3 years ago
10

How do you solve 2A= 4lw+2Lh+6wH for w

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

Answer:

\displaystyle w=\frac{A-Lh}{2l+3H}

Explanation:

Solving Equations by Isolation

We have this equation:

2A= 4lw+2Lh+6wH

Let's solve it for w step by step. First, we flip both sides

4lw+2Lh+6wH =2A

Subtracting 2Lh in both sides

4lw+2Lh+6wH-2Lh =2A-2Lh

Simplifying

4lw+6wH =2A-2Lh

Factoring w

w(4l+6H) =2A-2Lh

Dividing by (4l+6H)

\displaystyle w=\frac{2A-2Lh}{4l+6H}

Simplifying by 2:

\displaystyle \boxed{w=\frac{A-Lh}{2l+3H}}

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Explanation:

4 0
3 years ago
2. An electric motor transfers 2003 in 10.0 s. If it then transfers the same amount of energy in 8.0 s, has its
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Answer:

decreased

Explanation:

because it transfered from 10.0s

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2 years ago
F each fission reaction in a nuclear reactor emits three neutrons, how many neutrons are produced from three fission reactions?
IrinaK [193]

The Three fission reactions will produce nine neutrons

<h3>Meaning of Fission</h3>

Fission can be defined as a nuclear process that involves the breaking of a whole nuclear matter into smaller bits.

In a fission reaction, the matter is broken down into simpler bits.

In conclusion, The Three fission reactions will produce nine neutrons

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8 0
2 years ago
15) A 328-kg car moving at 19.1 m/s in the +x direction hits from behind a second car moving at 13 m/s in the same direction. If
kolbaska11 [484]

Answer:

Explanation:

Given that,

Mass of first car

M1= 328kg

The car is moving in positive direction of x axis with velocity

U1 = 19.1m/s

Velocity of second car

U2 = 13m/s, in the same direction as the first car..

Mass of second car

M2 = 790kg

Velocity of second car after collision

V2 = 15.1 m/s

Velocity of first car after collision

V1 =?

This is an elastic collision,

And using the conservation of momentum principle

Momentum before collision is equal to momentum after collision

P(before) = P(after)

M1•U1 + M2•U2 = M1•V1 + M2•V2

328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1

16534.8 = 328•V1 + 11929

328•V1 = 16534.8—11929

328•V1 = 4605.8

V1 = 4605.8/328

V1 = 14.04 m/s

The velocity of the first car after collision is 14.04 m/s

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3 years ago
A 70 kg object is on a table in static equilibrium. What is the support (normal) force the table exerts on the box
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