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vovikov84 [41]
3 years ago
10

How do you solve 2A= 4lw+2Lh+6wH for w

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

Answer:

\displaystyle w=\frac{A-Lh}{2l+3H}

Explanation:

Solving Equations by Isolation

We have this equation:

2A= 4lw+2Lh+6wH

Let's solve it for w step by step. First, we flip both sides

4lw+2Lh+6wH =2A

Subtracting 2Lh in both sides

4lw+2Lh+6wH-2Lh =2A-2Lh

Simplifying

4lw+6wH =2A-2Lh

Factoring w

w(4l+6H) =2A-2Lh

Dividing by (4l+6H)

\displaystyle w=\frac{2A-2Lh}{4l+6H}

Simplifying by 2:

\displaystyle \boxed{w=\frac{A-Lh}{2l+3H}}

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A thin partition divides a thermally insulated vessel into a lower compartment of volume V and an upper compartment of volume 2V
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Answer:

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S_{f}-S_{i}=nRln(\frac{V_{F}}{V_{I}})\\

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since the process is n adiabatic free expansion, the entropy of the system is constant. Hence we can re-write the equation as

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