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Natalka [10]
3 years ago
7

A reducing elbow in a horizontal pipe is used to deflect water flow by an angle θ = 45° from the flow direction while accelerati

ng it. The elbow discharges water into the atmosphere. The cross- sectional area of the elbow is 150 cm2 at the inlet and 25 cm2 at the exit. The elevation difference between the centers of the exit and the inlet is 40 cm. The mass of the elbow and the water in it is 50 kg. Determine the anchoring force needed to hold the elbow in place. Take the momentum flux correction factor to be 1.03 at both the inlet and outlet.

Physics
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

915 N is the anchoring force needed to hold the elbow in place.

Explanation:

Momentum equation:

∑

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¡Hola!

For this problem, first, lets recabe information:

v = 0 m/s

t = 3 s

g = 9,82 m/s²

v' = ?

d = ?

First, for calculate the final velocity:

v' = v + g * t

v' = 0 m/s + 9,82 m/s² * 3 s

v' = 29,46 m/s \leftarrow \boxed{\text{Velocity} }

Now, for calculate how far did it fall:

d = v * t + g * t^2 / 2

Like v = 0 m/s, we can simplificate equation:

d = g * t^2 / 2

d = 9,82 m/s² * (3 s)^2 / 2

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5 0
3 years ago
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goldfiish [28.3K]

Answer:

4km

Explanation:

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Knowing this we know the time and speed

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How to light prodeced by nature
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ch4aika [34]

Answer:

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Explanation:

Given;

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Y_Kistochka [10]

Answer:

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Explanation:

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3 years ago
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