Answer: C Plane
Explanation: According to Newton's law, gravitational force is proportional to the product of masses and inversely proportional to the square of distance between them.
Gravitational force depends on mass. The bigger the mass, the more the magnitude of the gravitational force. Since plane is assume to have the highest mass in the options, we can therefore conclude that plane will experience the highest gravitational force.
The answer to your question is Speed
Answer:
3.6 KJ
Explanation: Given that a 70-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.60 m, and ends with a speed of 8.5 m/s. How much nonconservative work (in kJ) was done on the boy
The workdone = the energy.
There are two different energies in the scenario - the potential energy (P.E ) and the kinetic energy ( K.E )
P.E = mgh
P.E = 70 × 9.8 × 1.6
P.E = 1097.6 J
P.E = 1.098 KJ
K.E = 1/2mv^2
K.E = 1/2 × 70 × 8.5^2
K.E = 2528.75 J
K.E = 2.529 KJ
The non conservative workdone = K.E + P.E
Work done = 1.098 + 2.529
Work done = 3.63 KJ
Therefore, the non conservative workdone is 3.6 KJ approximately
Answer:
11.95m/s
Explanation:
A moving object has a kinetic energy of 150 J and a momentum of 25.1 kg·m/s.
a) Find the speed of the object. Answer in units of m
K. E =½mv²
150= ½mv²
Multiply both sides by 2
mv² = 300
Divide both sides by v²
m = 300/v² .................. Equation 1
Momentum is the product of mass and velocity
Momentum = mv
25.1 = mv
Divide both sides by v
m = 25.1/v ................ Equation 2
Equate equations 1 and 2
300/v² = 25.1/v
Cross multiply
25.1v² = 300v
Multiply v with both sides
25.1v = 300
Divide both sides by 25.1
v = 300/25.1
V = 11.95m/s
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Answer:
Total mechanical energy is the sum of potential energy plus kinetic energy. The kinetic energy will be 250 [J] and the potential energy is zero, therefore Total mechanical energy will be 250 + 0 =250[J]
Explanation:
This is a problem that applies the principle of energy conservation, i.e. mechanical energy that will be transformed into kinetic energy. We need to identify what kind of energy we have depending on the position of the ball with respect to the reference axis we take.
The reference axis or reference point is the point at which the potential energy is equal to zero, for this case we will take the ground as our reference point.
We know that the potential energy is defined by:
![E_{p}=m*g*h\\ where:\\m=mass[kg]\\g=gravity[m/s^2]\\h=elevation[m]](https://tex.z-dn.net/?f=E_%7Bp%7D%3Dm%2Ag%2Ah%5C%5C%20where%3A%5C%5Cm%3Dmass%5Bkg%5D%5C%5Cg%3Dgravity%5Bm%2Fs%5E2%5D%5C%5Ch%3Delevation%5Bm%5D)
We can clear the mass from this equation:
![m=\frac{E_{p} }{(g*h)} \\m=\frac{250 }{(9.81*5)} \\\\m=5.09[kg]](https://tex.z-dn.net/?f=m%3D%5Cfrac%7BE_%7Bp%7D%20%7D%7B%28g%2Ah%29%7D%20%5C%5Cm%3D%5Cfrac%7B250%20%7D%7B%289.81%2A5%29%7D%20%5C%5C%5C%5Cm%3D5.09%5Bkg%5D)
When this body falls its potential energy will decrease but its kinetic energy will increase and reach its maximum value when the ball reaches the ground.
In such a way that its potential energy would be transformed into kinetic energy.
![E_{k} = E_{p} \\E_{k} =kinetic energy [J]](https://tex.z-dn.net/?f=E_%7Bk%7D%20%3D%20E_%7Bp%7D%20%5C%5CE_%7Bk%7D%20%3Dkinetic%20energy%20%5BJ%5D)
Since the potential energy has been transformed all into kinetic energy the amount of energy is conserved, therefore the total mechanical energy will remain the same.
