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Nina [5.8K]
3 years ago
9

If vector b is added to vector a under what conditions does the resultant vector has magnitude a+b?​

Physics
2 answers:
Softa [21]3 years ago
7 0

Explanation:

hope it's useful for you knows

Citrus2011 [14]3 years ago
5 0

The vectors must point in the same direction.

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Solve the equation. 5x-5=10x+2
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Answer:

x = - 1.4

Explanation:

-5=10x+2-5x     (subtract 5x from both sides)

-5=5x+2     (simplify)

-5-2=5x     (subtract 2 from both sides)

-7=5x      (simplify)

x=-7/5     (divide both sides by 5)

x=-1.4    (simplify)

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An object, initially at rest, moves 250 m in 17 s. What is its acceleration?
mash [69]

Answer:

1.73 m/s²

Explanation:

Given:

Δx = 250 m

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t = 17 s

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a = 1.73 m/s²

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What is the seventh planet from the sun?
stiv31 [10]

The seventh planet from the sun is Uranus.

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What is the magnitude of the applied electric field inside an aluminum wire of radius 1.2 mm that carries a 3.0-a current? [ σal
galben [10]
Hello

1) First of all, since we know the radius of the wire (r=1.2~mm=0.0012~m), we can calculate its cross-sectional area
A=\pi r^2 = 3.14 \cdot (0.0012~m)^2=4.5\cdot10^{-6}~m^2

2)  Then, we can calculate the current density J inside the wire. Since we know the current, I=3~A, and the area calculated at the previous step, we have
J= \frac{I}{A}= \frac{3~A}{4.5\cdot10^{-6}~m^2} = 6.63\cdot10^5 ~A/m^2

3) Finally, we can calculate the electric field E applied to the wire. Given the conductivity \sigma=3.6\cdot10^7~ \frac{A}{Vm} of the aluminium, the electric field is given by
E= \frac{J}{\sigma}= \frac{ 6.63\cdot10^5 ~A/m^2}{3.6\cdot10^7~ \frac{A}{Vm} } = 0.018~V/m

4 0
3 years ago
Explain a charged by neutral body negatively by induction
Tpy6a [65]
If a negatively charged object is used to charge a neutral object by induction, then the neutral object will acquire a positive charge. And if a positively charged object is used to charge a neutral object by induction, then the neutral object will acquire a negative charge.
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