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Nina [5.8K]
3 years ago
9

If vector b is added to vector a under what conditions does the resultant vector has magnitude a+b?​

Physics
2 answers:
Softa [21]3 years ago
7 0

Explanation:

hope it's useful for you knows

Citrus2011 [14]3 years ago
5 0

The vectors must point in the same direction.

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A watermelon is blown into three pieces by a large firecracker. Two pieces of equal mass m fly away perpendicular to one another
Alenkinab [10]

Answer:

Speed of larger piece is \dfrac{V\sqrt{2}}{3}

Explanation:

We apply the principle of conservation of momentum.

The watermelon is initially at rest. The initial momentum = 0 kg m/s in all directions.

After the collision,

Vertical momentum = momentum of piece in y-direction + y-component of momentum of larger piece = mV + 3mv_{ly}

Here, v_{ly} is the y-component of velocity of larger piece.

This is equal to 0, since the initial momentum is 0.

v_{ly}=\dfrac{V}{3}

Horizontal momentum = momentum of piece in x-direction + x-component of momentum of larger piece = mV + 3mv_{lx}

Here, v_{lx} is the x-component of velocity of larger piece.

This is also equal to 0, since the initial momentum is 0.

v_{lx}=\dfrac{V}{3}

The velocity of the larger piece, v_l, is the resultant of v_{lx} and v_{ly}. Since they are mutually perpendicular,

v_l = \sqrt{v_{ly}^2+v_{lx}^2}= \sqrt{\left(\dfrac{V}{3}\right)^2+\left(\dfrac{V}{3}\right)^2}

v_l = \dfrac{V\sqrt{2}}{3}

3 0
4 years ago
How will air resistance affect a falling object?
Greeley [361]
<span>Air resistance, also called drag, acts upon a falling body by slowing the body down to the point where it stops accelerating, and it falls at a constant speed, known as the terminal velocity of a falling object. Air resistance depends on the cross-sectional area of the object, which is why the effect of air resistance on a large flat-surfaced object is much greater than on a small, stream-lined object.</span>
6 0
3 years ago
What do you think will happen to dirt and rocks on the Mountainside when the ice melts
AlekseyPX
This question is personal preference... just answer with whatever YOU think, there probably isn’t s wrong answer if I’d guess.
3 0
3 years ago
Helpppp!! On which surface is the student not able to move the box?
LenKa [72]

Answer:

d

Explanation:

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3 0
3 years ago
A fish is 17.9 cm from the front surface of a fish bowl of radius 45 cm. Where does the fish appear to be to someone in air view
AleksAgata [21]

Answer:

Fish will appear at distance 14.9 cm from the surface of bowl

Explanation:

As we know that fish is floating inside the water in fish bowl while it is observed from outside in air

so we have

\frac{\mu_2}{d_i} - \frac{\mu_1}{d_o} = \frac{\mu_2 - \mu_1}{R}

here we have

\mu_2 = 1

\mu_1 = 1.33

d_o = 17.9 cm

R = 45 cm

now we have

\frac{1}{d_i} - \frac{1.33}{17.9} = \frac{1 - 1.33}{45}

d_i = 14.9 cm

7 0
4 years ago
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