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ra1l [238]
3 years ago
14

A student estimated the volume of a liquid in a beaker as 200.0 mL. When she poured the liquid into a graduated cylinder she MEA

SURED the volume to be 198.2 mL. What is the percent error?
Chemistry
1 answer:
Taya2010 [7]3 years ago
6 0

Answer:

<h3>The answer is 0.91 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual volume = 198.2 mL

error = 200 - 198.2 = 1.8

So we have

P(\%) =  \frac{1.8}{198.2}  \times 100 \\  = 0.90817356205...

We have the final answer as

<h3>0.91 %</h3>

Hope this helps you

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How much heat is required to raise the temperature of 670g of water from 25.7"C to 66,0°C? The specific heat
inna [77]

Answer:

Explanation:

q= mc theta

where,

Q = heat gained

m = mass of the substance = 670g

c = heat capacity of water= 4.1 J/g°C    

theta =Change in temperature=( 66-25.7)

Now put all the given values in the above formula, we get the amount of heat needed.

q= mctheta

q=670*4.1*(66-25.7)

  =670*4.1*40.3

=110704.1

8 0
3 years ago
Which is one characteristic of producers?
ludmilkaskok [199]

Answer: They use other organisms for energy

Explanation:

8 0
3 years ago
A solution is prepared by dissolving 15.0 g of nh3 in 250.0 g of water. the density of the resulting solution is 0.974 g/ml. the
sergeinik [125]
The formula for molality---> m = moles solute/ Kg of solvent

the solute here is NH₃ because it's the one with less amount. which makes water the solvent.

1) let's convert the grams of NH₃ to moles using the molar mass

molar mass of NH₃= 14.0 + (3 x 1.01)= 17.03 g/ mol

15.0 g (1 mol/ 17.03 g)= 0.881 mol NH₃

2) let's convert the grams of water into kilograms (just divide by 1000)

250.0 g= 0.2500 kg

3) let's plug in the values into the molality formula

molality= mol/ Kg---> 0.881 mol/ 0.2500 kg= 3.52 m
6 0
3 years ago
A solution of an unknown nonvolatile nonelectrolyte was prepared by dissolving 0.250 g of the substance in 40.0 g of ccl4. the b
Finger [1]
Answer : The molar mass of the solute will be 87.90 g/mol.

Explanation : We know the formula for elevation in boiling point, which is

Δt = iK_{b}m

given that, Δt = 0.357, K_{b} = 5.02 and mass of CCl _{4} = 40,

on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X10^{-3}. 
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3 0
3 years ago
(IMAGE ATTACHED)<br>(pls help this is due tonight)<br>​
miv72 [106K]

Answer:

You can see that the line is going up and is curved in a positive direction.

Explanation:

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5 0
3 years ago
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