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ra1l [238]
3 years ago
14

A student estimated the volume of a liquid in a beaker as 200.0 mL. When she poured the liquid into a graduated cylinder she MEA

SURED the volume to be 198.2 mL. What is the percent error?
Chemistry
1 answer:
Taya2010 [7]3 years ago
6 0

Answer:

<h3>The answer is 0.91 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual volume = 198.2 mL

error = 200 - 198.2 = 1.8

So we have

P(\%) =  \frac{1.8}{198.2}  \times 100 \\  = 0.90817356205...

We have the final answer as

<h3>0.91 %</h3>

Hope this helps you

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ankoles [38]

Answer:

C, physical change

Explanation:

take a look at the equation. Next to each form of water do you see the little (g) and (l)? These represent the state of matter the water is in. So, the water is going from a gas to a liquid. The chemical compound is the same so its a physical change, not chemical, and it is reversible. You could change the liquid water back to the gas through evaporation. Endothermic has literally nothing to do with this equation so you can easily eliminate that answer choice.

7 0
3 years ago
Sodium metal reacts with aluminum chloride to produce sodium chloride and aluminum. The balanced reaction is: 3 Na(s) + AlCl3(aq
andre [41]
First convert 12.0g of Na to moles using the grams to moles conversation and you get about .5219 moles (I didn't use significant figures). Divide that number by 3 because that is the coefficient of Na and you will get about .17398 moles, which is how many moles are in 1. Since Al has a coefficient of 1, .17398 woild be your final answer
3 0
3 years ago
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Kobotan [32]
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6 0
3 years ago
What is oxidation number on Ni in the next compound<br> K2[NiBr6] ???
ziro4ka [17]

Explanation:

The oxidation number of Ni is +4

4 0
3 years ago
How do you solve this ??
ICE Princess25 [194]

Answer:

Option D. 400 mmHg

Explanation:

The following data were obtained from the question:

Mole of He (nHe) = 0.04 mole

Mole of Ne (nNe) = 0.06 mole

Total pressure = 10³ mmHg

Partial pressure of He =.?

Next, we shall determine the total number of mole in the reaction vessel.

This can be obtained as follow:

Mole of He (nHe) = 0.04 mole

Mole of Ne (nNe) = 0.06 mole

Total mole =?

Total mole = nHe + nNe

Total mole = 0.04 + 0.06

Total mole = 0.1

Next, we shall determine the mole fraction of He.

This can be obtained as follow:

Mole fraction = mole of gas /total mole

Mole of He (nHe) = 0.04 mole

Total mole = 0.1

Mole fraction of He =.?

Mole fraction of He = nHe/total mole

Mole fraction of He = 0.04/0.1

Mole fraction of He = 0.4

Finally, we shall determine the partial pressure of He as follow:

Partial pressure = mole fraction x total pressure

Mole fraction of He = 0.4

Total pressure = 10³ mmHg

Partial pressure of He =.?

Partial pressure of He = 0.4 x 10³

Partial pressure of He = 400 mmHg.

Therefore, the partial pressure of He is 400 mmHg.

8 0
3 years ago
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