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Nat2105 [25]
2 years ago
10

Question 2 of 10

Chemistry
1 answer:
antiseptic1488 [7]2 years ago
3 0

Answer:

law of conservation of matter

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Interaction of Orchids on A tree? ​
ziro4ka [17]

Answers:

<h2>The symbiotic relationship that occurs between an orchid and a tree would be classified as commensalism. Most orchids are epiphytes, which mean that that they grow on other plants. This benefits the orchids because they can grow on top of the canopy, which prevents the orchids from being walked on or eaten by ground-dwelling organisms.</h2><h3 /><h3>I HOPE TO IT'S HELP YOU:)</h3>

3 0
2 years ago
10 points<br><br> How many more oxygen atoms are in 3Mg3(PO4)2 than in 4Al2O3?
Feliz [49]

Answer:

12 more oxygen

Explanation:

An atom is the smallest particles that can take part in a chemical reaction

The given compounds are:

        3Mg₃(PO₄)₂  

 Number of oxygen atoms  = 3[2 x 4]  = 24 oxygen atoms

For;

             4Al₂O₃;

   Number of oxygen atoms  = 4 x 3  = 12 oxygen atoms

In   3Mg₃(PO₄)₂  , there are 24  - 12  = 12 more oxygen atoms than in  4Al₂O₃;

6 0
2 years ago
Read 2 more answers
In the Bronsted-Lowry model of acids and bases, a(n) _____ is a hydrogen donor and a(n) _____ is a hydrogen acceptor.
ExtremeBDS [4]
<span>In the Bronsted-Lowry model of acids and bases, a(n) _acid____ is a hydrogen donor and a(n) _base____ is a hydrogen acceptor.</span>
5 0
3 years ago
Question 3(1 point)
SVETLANKA909090 [29]

Answer:

<u><em>Group 8 is a group (column) of chemical elements in the periodic table. It consists of iron (Fe), ruthenium (Ru), osmium (Os) and hassium (Hs). They are all transition metals.</em></u>

Explanation:

5 0
2 years ago
A chemist prepares a sample of helium gas at a certain pressure, temperature and volume and then removes all but a fourth of the
cupoosta [38]

Answer:

The temperature must be changed to 4 times of the initial temperature so as to keep the pressure and the volume the same.

Explanation:

Pressure in the container is P and volume is V.

Temperature of the helium gas molecules =T_1

Molecules helium gas = x

Moles of helium has = n_1= \frac{x}{N_A}

PV = nRT (Ideal gas equation)

PV=n_1RT_1...[1]  

After removal of helium gas only a fourth of the gas molecules remains and pressure in the container and volume should remain same.

Molecules of helium left after removal = \frac{x}{4}

Moles of helium has left after removal = n_2= \frac{x}{4\times N_A}

PV=n_2RT_2...[2]

n_1RT_1=n_2RT_2

\frac{x}{N_A}\times T_1=\frac{x}{4\times N_A}\times T_2

T_1=\frac{T_2}{4}

T_2=4T_1

The temperature must be changed to 4 times of the initial temperature so as to keep the pressure and the volume the same.

6 0
3 years ago
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