Answer:
98
Explanation:
Based on the reaction:
NaOH + H2SO4 → NaHSO4 + H2O
<em>Where 1 mole of the base (NaOH) reacts per mole of the acid (H2SO4)</em>
<em />
The formula of equivalent weight is:
Equivalent weight = Molecular mass / Number of equivalent moles
<em>Where Molecular mass of sulfuric acid is 98g/mol</em>
<em>And number of equivalent moles = 1 -Because 1 mole of acid reacts per mole of base</em>
<em />
Equivalent weight is:
98 / 1 =
98
Answer:
that it was orginal a water source
Explanation:
A is the answer that ud be looking for in chemistry :)
Answer:
Ksp = 3.47x10⁻⁹
Explanation:
When Lead (II) iodide (PbI₂) is added to water, the equilbrium produced is:
PbI₂(s) → Pb²⁺(aq) + 2 I⁻(aq)
And solubility product constant, ksp is:
Ksp = [Pb²⁺] [I⁻]²
A solubility of 9.54x10⁻⁴ M means the maximum concentration of Pb²⁺ is 9.54x10⁻⁴ M and 9.54x10⁻⁴ M×2 of I⁻. Replacing in ksp formula:
Ksp = [9.54x10⁻⁴] [2×9.54x10⁻⁴]²
<em>Ksp = 3.47x10⁻⁹</em>
The given statement is true .
<h3>What is Rutherford’s gold foil experiment?</h3>
- A piece of gold foil was hit with alpha particles, which have a favorable charge. Most alpha particles went right around. This showed that the gold particles were mostly space.
- The Rutherford gold leaf investigation supposed that most (99%) of all the mass of an atom is in the middle of the atom, that the nucleus is very small (105 times small than the length of the atom) and that is positively captured.
- For the distribution experiment, Rutherford enjoyed a metal sheet that could be as thin as practicable. Gold is the most malleable of all known metals. It can easily be converted into very thin sheets. Hence, Rutherford established a gold foil for his alpha-ray scattering experimentation.
To learn more about Rutherford’s gold foil experiment, refer to:
brainly.com/question/4113533
#SPJ4
