Mass of Cyclohexen : 10.2 g
<h3>Further explanation</h3>
Reaction
3 C6H10 + 4 Na2Cr2O7 + 16 H2SO4 >
3 C6H10O4 + 4 Cr2(SO4)3 + 4Na2SO4 + 16 H2O
mol C6H10 : mol C6H10O4 = 3 : 3 = 1 : 1

12.5 grams of C6H10O4 , mol C6H10O4 (MW 146.14 g/mol):

mol C6H10 = mol C6H10O4 = 0.124
mass C6H10 :

Answer:
Explanation:
Atom 1 and 4 because they have the same number of valence elctrons in its outermost shell
Answer:
The question asks for moles, which can be obtained from P-V-T data using the ideal gas
equation: n =
RT
PV .
Now use the rearranged gas law to determine the number of moles in the sample:
!
n = PV
RT = (6.47 x 105 Pa)(5.65 x 10-4m3
)
(8.314 J
mol K )(21.7 + 273.15 K) = 0.149 mol.
All conditions except the pressure and volume are fixed, so P1V1 = P2V2 can be used: 3.62 L
101kPa
(647 kPa)(0.565 L)
2
1 1
2 = =
P
PV V
Explanation:
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density 15.4 grams per 1.2³ cm³ ≅ 8.9 grams per cm³
<span>Find the metal that has a density of approximately 8.9 g/cm³</span>