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3 years ago

What must models and theories do in order to remain valid? Provide 2 facts.

Chemistry

2 answers:

Sunny_sXe [5.5K]3 years ago

8 0

Answer:

1. Models and theories should explain known fact.

2. Models and theories should enable scientists to make accurate deductions and predictions.

Explanation:

A model involves the use of a physical, conceptual, or mathematical representation to describe a real phenomenon that could not be understood by mere direct observation. It could be in the form of a diagram or picture, aircraft model kit etc.

A theory is a well tested and confirmed phenomenon through repeated observations and experiments. It is a stronger assertion that explains the facts about a phenomenon. Such are not guesses or mere saying, but reliable accounts of some phenomenon in the real world.

Therefore for models and theories to be valid, they must explain known facts and enable scientists to make accurate predictions.

Andrews [41]3 years ago

6 0

Do what they was made to do

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Which statement correctly describes potassium iodide, KI? There is a one-to-one ratio of potassium ions to iodide ions. Potassiu

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The answer is there is a one-to-one ratio of potassium ions to iodide ions.

Explanation :

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3 years ago

Read 2 more answers

How many grams of nan3 are required to produce 19.0 ft3 of nitrogen gas, about the size of an automotive air bag, if the gas has

Papessa [141]

The balanced chemical reaction is given as:

$2NaN_{3}(s)\rightarrow 2Na(s)+3N_{2}(g)$

Now, convert $19.0 ft^{3}$ into litres.

$1 ft^{3} = 28.3168$

So, $19.0 ft^{3} = 19\times 28.3168 = 538.0192 L$

Density is equal to the ratio of mass to the volume.

$D=\frac{M}{V}$

where, M = mass and V= volume $(538.0192 L)$

Substitute the value of density and volume in formula to get the value of mass.

$1.25 g/L=\frac{M}{538.0192 L}$

$1.25 g/L\times 538.0192 L= M$

$Mass = 672.524 g$

Now, number of moles of $N_{2}$ gas= $\frac{672.524 g}{28.02 g/mol}$

= $24.00 moles$

According to the reaction, 2 moles of sodium azide gives 3 moles of nitrogen gas.

Now, in 24.00 moles of nitrogen gas produced from= $\frac{2 moles of sodium azide}{3 moles of nitrogen gas}\times 24.00 moles$ of nitrogen gas, moles of sodium azide.

number of moles of sodium azide = $16 moles$

Mass of sodium azide in g = $number of moles\times molar mass of sodium azide$ .

= $16 moles\times 65.00 g/mol$

= $1040 g$

Thus, mass of sodium azide which is required to produce $19.0 ft^{3}$ of nitrogen gas = $1040 g$

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