A. The atmosphere
All the other examples are either elements or compounds, not mixtures. A mixture is a combination of elements that are not chemically or irreversibly conjoined so the atmosphere, made up of a variety of gases, would be a mixture.
Given what we know, we can confirm that in a voltaic cell, the anode loses electrons and is oxidized, meanwhile, the cathode is reduced by gaining electrons.
<h3 /><h3>What is a voltaic cell?</h3>
- It is described as an electrochemical cell.
- These cells use chemical reactions to produce electrical energy.
- During this reaction, an anode loses electrons, thus oxidizing.
- Meanwhile, the cathode gains electrons and is reduced.
Therefore, given the nature of the voltaic cell, we can confirm that during its reaction, the anode is oxidized by losing electrons while the cathode becomes reduced by gaining them.
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Answer:
All of the above.
Explanation:
Hello there!
In this case, according to the definition of the Lewis structures, which are represented by the valence electrons, we first identify that the N atom has five valence electrons and each fluorine has seven valence electrons.
In such a way, we cans say that N is the central atom due to its lower electronegativity, the molecule has 7+7+7+5=26 valence electrons and the three F-N bonds are covalent, therefore the answer is all of the above.
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Ionic bonds generally have higher melting points due to stronger electrostatic interactions.
Answer: 
Explanation: The given chemical reaction is:
Equilibrium constant (Kc) in general is written as:
![K_c=\frac{[products]}{[reactants]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5Bproducts%5D%7D%7B%5Breactants%5D%7D)
Note:- Coefficients are written as their powers
So, the Kc expression for the above reaction will be:
![K_c=\frac{[NO]^2[Br_2]}{[NOBr]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO%5D%5E2%5BBr_2%5D%7D%7B%5BNOBr%5D%5E2%7D)
Equilibrium moles are given for all of them. Let's divide the moles by given liters to get the concentrations.
![[NOBr]=\frac{0.412mol}{10.3L}](https://tex.z-dn.net/?f=%5BNOBr%5D%3D%5Cfrac%7B0.412mol%7D%7B10.3L%7D)
= 0.040 M
![[NO]=\frac{0.678mol}{10.3L}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Cfrac%7B0.678mol%7D%7B10.3L%7D)
= 0.0658 M
![[Br_2]=\frac{0.224mol}{10.3L}](https://tex.z-dn.net/?f=%5BBr_2%5D%3D%5Cfrac%7B0.224mol%7D%7B10.3L%7D)
= 0.0217 M
Plug in the values in the equilibrium expression to calculate Kc.
