The volume is 19.76987448 by taking the known variables mass=18.9g and density=0.956g/ml
To get volume you divide the mass by the density which gives you about
19.77 ml in volume

6 0

3 years ago

QUESTION 4

Nikolay [14]

Answer:

False

Explanation:

According to kinetic molecular theory, all collisions are perfectly elastic and energy is conserved.

3 0

3 years ago

For the reaction represented by the equation 2KClO3 → 2KCl + 3O2, how many grams of potassium chlorate are required to produce 1

Vikentia [17]

The grams of potassium chlorate that are required to produce 160 g of oxygen is 408.29 grams

calculation

2 KClO₃→ 2 KCl + 3O₂

Step 1: find the moles of O₂

moles = mass÷ molar mass

from periodic table the molar mass of O₂ = 16 x2 = 32 g/mol

moles = 160 g÷ 32 g/mol = 5 moles

Step2 : use the mole ratio to determine the moles of KClO₃

from equation given KClO₃ : O₂ is 2:3

therefore the v moles of KClO₃ = 5 moles x 2/3 = 3.333 moles

Step 3: find the mass of KClO₃

mass= moles x molar mass

from periodic table the molar mass of KClO₃

= 39 + 35.5 + (16 x3) =122.5 g/mol

mass = 3.333 moles x 122.5 g/mol =408.29 grams

7 0

3 years ago

At a certain temperature a 42.55% (v/v) solution of ethyl alcohol, C2H5OH, in water has a density of 0.9027 g mL-1. The density

swat32

Answer:

a. 7.187M.

b. 7.962m.

c. 0.1846

Explanation:

This solution contains 42.55mL of ethyl alcohol in 100mL of solution.

a. Molar concentration = Moles ethyl alcohol / L solution:

Moles ethyl alcohol -Molar mass: 46.07g/mol-

42.55mL * (0.7782g/mL) * (1mol / 46.07g) = 0.7187 moles ethyl alcohol

Liters solution:

100mL * (1L / 100mL) = 0.100L

Molar concentration: 0.7187mol / 0.100L = 7.187M

b. Molal concentration: Moles ethyl alcohol (0.7187moles) / kg solution

kg solution:

100mL * (0.9027g / mL) * (1kg / 1000g) = 0.09027kg

Molal concentration: 0.7187mol / 0.09027kg = 7.962m

c. Mole fraction: Moles ethyl alcohol / Moles ethyl alcohol + moles water

Moles water: -molar mass: 18.01g/mol-

Volume water = 100mL - 42.55mL = 57.45mL

57.45mL * (0.9949g/mL) * (1mol/18.01g) = 3.1736 moles water

Moles fraction:

0.7187 moles ethyl alcohol / 0.7187 moles ethyl alcohol+3.1736 moles water

= 0.1846

4 0

3 years ago