Your first step should be to analyse the compound. For example, if the compound is carbon, you know it always has a valence of four, so, if it has a formula C2H4 (ethylene) it obviously has a double bond. There are difficulties here because benzene C6H6 can be considered to have 6 1.5 C-C bonds, being aromatic.
A second step is to look at its structure. Double bonds are traditionally shorter than single bonds; triple bonds shorter still. Covalent bonds do have typical lengths, nevertheless you can still have problems.
<span>A third step is to consider reactivity. For example, if you have a C=C double bond, you can add, say, bromine to it Thus C2H4 gives C2H4Br2, and by adding two bromine atoms you know you have one double bond. Again, benzene becomes an awkward molecule, but because of this, you know benzene does not have double bonds in the traditional sense</span>
Answer:
3
Explanation:
third answer might be right
Answer:Velocity, one of the most frequently used tools for evaluating pitchers, represents the maximum speed of a given pitch at any point from its release to the time it crosses home plate.
Explanation:Velocity, one of the most frequently used tools for evaluating pitchers, represents the maximum speed of a given pitch at any point from its release to the time it crosses home plate.
Answer:
Number of moles = 1.57 mol
Explanation:
Given data:
Mass of propanol = 94.1 g
Molar mass of propanol = 60.1 g/mol
Number of moles of propanol = ?
Solution:
Formula:
Number of moles = mass/molar mass
by putting values,
Number of moles = 94.1 g/ 60.1 g/mol
Number of moles = 1.57 mol
Answer is: mass of water is 432 grams.
Chemical reaction: 2H₂ + O₂ → 2H₂O.
m(O₂) = 384 g.
M(O₂) = 2 · 16 g/mol = 32 g/mol, molar mass.
n(O₂) = m(O₂) ÷ M(O₂).
n(O₂) = 384 g ÷ 32 g/mol.
n(O₂) = 12 mol, amount of substance.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 12 mol · 2 = 24 mol.
m(H₂O) = n(H₂O) · M(H₂O).
m(H₂O) = 24 mol · 18 g/mol.
m(H₂O) = 432 g.
