Answer:
c) What is the ratio K2/K1 of their kinetic energies?
Explanation:
<span>T(t)=60+140<span>e<span>−0.075t</span></span></span>
<span>T(12)=60+140<span>e<span>−0.075∗12</span></span></span>
<span>T(12)=60+140<span>e<span>−0.9</span></span></span>
<span><span>T(12)=60+140(0.4065696597)
=116.84
So the temperature will be approximately 117 degrees</span></span>
7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J
8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m
9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333
Answer:
1963.93 Moles
Explanation:
-We know the standard conversion ratio for the volume of a mole is 
Given volume of rooms as 
Convert the volume into liters:
#From our conversion ratio above, we get the volume of air molecules in moles as:
Hence, the volume of air molecules is 1963.93 Moles
