Question

A 2.53 kg particle has a velocity of vx = 6.8 m/s and vy = 7.21 m/s. Find the magnitude of its total momentum. Answer in units of kg · m/s.

Answer 1

Answer:

25.05 kg m/s

Explanation:

mass, m = 2.53 m/s

vx = 6.8 m/s

vy = 7.21 m/s

Resultant velocity, $v = \sqrt{v_{x}^{2}+v_{y}^{2}}$

$v = \sqrt{6.8^{2}+7.21^{2}}$

v = 9.9 m/s

Momentum, p = mass x velocity

p = 2.53 x 9.9

p = 25.05 kg m /s