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ella [17]
4 years ago
10

A book falls off a shelf that is 10.0 m tall. What is the velocity at which the book hits the ground?

Physics
1 answer:
Elena L [17]4 years ago
8 0

Answer:

14 m/s

Explanation:

The motion of the book is a free fall motion, so it is an uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. Therefore we can find the final velocity by using the equation:

v^2 = u^2 + 2gd

where

u = 0 is the initial speed

g = 9.8 m/s^2 is the acceleration

d = 10.0 m is the distance covered by the book

Substituting data, we find

v=\sqrt{0^2 + 2(9.8 m/s^2)(10.0 m)}=14 m/s

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Answer:

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Explanation:

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NOTE: Length of the ramp is the Hypothenus i.e the longest side.

Let the Lenght of the ramp be 's'. The value of x can be obtained as follow:

s² = 4² + 3²

s² = 16 + 9

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Take the square root of both side

s = √25

s = 5 m

Thus the length of the ramp is 5 m

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Initial velocity (u) = 3 m/s

Acceleration (a) = 2 m/s²

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Final velocity (v) =?

v² = u² + 2as

v² = 3² + (2 × 2 × 5)

v² = 9 + 20

v² = 29

Take the square root of both side

v = √29

v = 5.39 m/s

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Initial velocity (u) = 3 m/s

Acceleration (a) = 2 m/s²

Final velocity (v) = 5.39 m/s

Time (t) =?

v = u + at

5.39 = 3 + 2t

Collect like terms

5.39 – 3 = 2t

2.39 = 2t

Divide both side by 2

t = 2.39 / 2

t = 1.2 s

Thus, it will take 1.2 s for the ball to get to the final position.

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